使用打印功能缩进的逻辑
我希望将“波浪”模式打印到控制台，例如：
/\
/ \
/
或者：
/\
/ \
\
\
最后，显示为一个大的多波：
/\ /\
/ \/ \
/ \
\
基于描述向上/向前或向下/向后方向/斜线中斜线数量的整数列表。我定义了两个函数，一个用于波的左侧最长，反之亦然：
from itertools import zip_longest
def left_wave(water_l, water_r):
"""When left side of wave is largest"""
l_str = " " * water_l + "/"
if water_r == 1:
r_str = "\\"
elif water_r:
r_str = " " * (water_r * 2 - 2) + "\\"
else:
r_str = ""
line = l_str + r_str
print(line)
def right_wave(water_l, water_r):
"""When right side of wave is largest"""
if water_l:
l_str = " " * water_l + "/"
factor_r = water_r * 2 - 2
else:
l_str = " "
factor_r = water_r * 2 - 2
r_str = " " * factor_r + "\\"
line = l_str + r_str
print(line)
我调用的print_sequence()定义如下：
def print_sequence(args):
"""Show all waves."""
for wave_height_l, wave_height_r in zip_longest(args[0::2], args[1::2], fillvalue=0):
for water_l, water_r in zip_longest(reversed(range(1, wave_height_l + 1)),
range(1, wave_height_r + 1),
fillvalue=0):
if wave_height_l > wave_height_r:
left_wave(water_l, water_r)
else:
right_wave(water_l, water_r)
运行如下：
args = [11, 2,
5, 7,
# 4
]
print_sequence(args)
目前返回：
/\
/ \
/
/
/
/
/
/
/
/
/
/\
/ \
/ \
/ \
/ \
\
\
我现在正在努力解决的主要问题是：我在right_wave函数中犯的逻辑错误是什么？（缩进是错误的）。此外，我将如何开始在同一行上打印 2 个波浪？也许end=""在打印函数调用中用作参数？
喵喵时光机2回答
-
慕码人2483693
如果list是您的选择，这里有一个打印波浪的简单方法：def print_wave(args): total_cols = sum(args) total_rows = args[0] # init total rows by first arg matrix = [[' ' for _ in range(total_cols)] for _ in range(total_rows)] curr_col = 0 curr_row = total_rows - 1 down = True for num in args: down = not down char = '\\' if down else '/' # update total rows and current row if need if down: diff = curr_row + num - total_rows if diff > 0: for _ in range(diff): matrix.append([' ' for _ in range(total_cols)]) total_rows += diff else: diff = num - 1 - curr_row if diff > 0: for _ in range(diff): matrix.insert(0, [' ' for _ in range(total_cols)]) total_rows += diff curr_row += diff for i in range(num): matrix[curr_row][curr_col] = char # for conjection not update curr row for the last loop if i != num - 1: if down: curr_row += 1 else: curr_row -= 1 curr_col += 1 for row in matrix: for col in row: print(col, end='') print()简单测试args=[3, 5, 4, 11, 2, 5, 7]： /\ / \ /\/ \ / \ \ / \ \/ \ \ \ \ \ / \ / \ /\ / \/ \ / \ / \ / \/希望这会有所帮助。 -
呼如林
当它是 python 2x 时，这很简单，它是由末尾的一个简单逗号完成的魔术，例如。Print("a"), Print("b") 输出：ab Incase of python 3x你必须使用。end=" " 控制下一个打印函数之间的空格
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Python