如何迭代打印多个值的过程？

Question

在这段 golang 代码中，我要求一个人输入他的名字。输入名称后，数据将从values1变量中获取，结果，它们将像这样使用给定的键打印出来

给定结果

Enter your name: samename

Here is the name: samename

Here is the email address: email one

Here is the job role: job one

我还想打印values2被注释的变量的数据。同样，如果我有值的数量，我是否必须一次又一次n地重复？for i := range values1

要求的结果

Enter your name: samename

Here is the name: samename

Here is the email address: email one

Here is the job role: job role one

Here is the name: samename

Here is the email address: email two

Here is the job role: job role two

...

...

代码

package main

import "fmt"

func main() {

    var name string

    keys := [3]string{"name", "email address", "job role"}

    values1 := [3]string{"samename", "email one", "job role one"}

    // values2 := [3]string{"samename", "email two", "job role two"}

    for {

        fmt.Printf("Enter your name: ")

        fmt.Scanln(&name)

        fmt.Println()

        if name == values1[0] {

            for i := range values1 {

                // j is index into keys

                j := i % len(keys)

                // Print blank line between groups.

                if j == 0 && i > 0 {

                    fmt.Println()

                }

                fmt.Printf("Here is the %s: %s\n", keys[j], values1[i])

            }

            break

        } else {

            fmt.Println("Name is not found. Try again!")

        }

    }

}

Answer 1

如果您需要打印密钥，也许您可以使用map. 你可以打印键和map值。package mainimport "fmt"func main() {    var name string    value1 := map[string]string{"name": "samename", "email": "email one", "role": "job role one"}    value2 := map[string]string{"name": "samename", "email": "email two", "role": "job role two"}    values := []map[string]string{value1, value2}    var found bool    for {        fmt.Printf("Enter your name: ")        fmt.Scanln(&name)        fmt.Println()        for _, value := range values {            if value["name"] == name {                found = true                for k, v := range value {                    fmt.Printf("Here is the %s: %s\n", k, v)                }                fmt.Println()            }        }        if found {            break        } else {            fmt.Println("Name is not found. Try again!")        }    }}