我正在学习 Go 并发并编写了强制性工作池示例,其中有 N 个工作和 M 个工作人员(N > M)。我遇到了一个死锁 ( all goroutines are asleep),我想不通;但是,我也在死锁发生之前得到了预期的输出,这让我更加困惑。有人可以指出我做错了什么吗?
我的代码是这样的:
package main
import (
"fmt"
"sync"
)
// A simple worker pool implementation using channels and WaitGroups.
// Our workers simply read from a channel of integers from an input
// channel and write their squares to an output channel.
func addJobs(jobsCh chan<- int, wg *sync.WaitGroup) {
// 100 numbers to crunch (jobs)
for i := 1; i < 101; i++ {
jobsCh <- i
}
wg.Done()
}
func worker(jobsCh <-chan int, resultsCh chan<- int, wg2 *sync.WaitGroup) {
for num := range jobsCh {
resultsCh <- num * num
}
wg2.Done()
}
func addWorkers(jobsCh <-chan int, resultsCh chan<- int, wg *sync.WaitGroup) {
var wg2 sync.WaitGroup
// 10 workers
for i := 0; i < 10; i++ {
wg2.Add(1)
go worker(jobsCh, resultsCh, &wg2)
}
wg.Done()
}
func readResults(resultsCh <-chan int, wg *sync.WaitGroup) {
for sq := range resultsCh {
fmt.Printf("%v ", sq)
}
wg.Done()
}
func main() {
var wg sync.WaitGroup
jobsCh := make(chan int)
resultsCh := make(chan int)
wg.Add(1)
go addJobs(jobsCh, &wg)
wg.Add(1)
go addWorkers(jobsCh, resultsCh, &wg)
wg.Add(1)
go readResults(resultsCh, &wg)
wg.Wait()
}
正如预期的那样,这会打印数字的平方(以随机顺序),但也会遇到死锁。请参阅此游乐场链接。:(
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