Python line_num 打印行号只输出最后的行号

Question

我正在尝试打印 .csv 文件的行号，但它只输出所有行的最后一个行号，这是我的代码：

import csv

openfile = open('example_csv.csv')

readcsv = csv.reader(openfile, delimiter = ',')

list_csv_content = list(readcsv)

for row in list_csv_content:

    print(f'Row #{readcsv.line_num} {row}')

输出是这样的：

Row #7 ['4/5/2015 13:34', 'Apples', '73']

Row #7 ['4/5/2015 3:41', 'Cherries', '85']

Row #7 ['4/6/2015 12:46', 'Pears', '14']

Row #7 ['4/8/2015 8:59', 'Oranges', '52']

Row #7 ['4/10/2015 2:07', 'Apples', '152']

Row #7 ['4/10/2015 18:10', 'Bananas', '23']

Row #7 ['4/10/2015 2:40', 'Strawberries', '98']

我究竟做错了什么？

Answer 1

当您将其保存readcsv到列表中时，您正在读取整个 csv，这就是 line_num 指向最后一行的原因。您可以通过不将 csv 保存到列表中来解决它：openfile = open('test.csv')readcsv = csv.reader(openfile, delimiter = ',')for line in readcsv:    print(line, readcsv.line_num)或者通过枚举列表：import csvopenfile = open('example_csv.csv')readcsv = csv.reader(openfile, delimiter = ',')list_csv_content = list(readcsv)for i, row in enumerate(list_csv_content):    print(f'Row #{i} {row}')

Answer 2

该line_num属性只是您的读者阅读的总行数。但是，以下代码应该可以在您enumerate获取实际行的位置加上该行的从零开始的索引。import csvopenfile = open('chart-images.csv')readcsv = csv.reader(openfile, delimiter = ',')list_csv_content = list(readcsv)for line_num, row in enumerate(list_csv_content):     print(f'Row #{line_num} {row}')切换为枚举，如@vks所示