不需要出图像，x,y,z,vx,vy,vz,x0,y0,z0,n都可以输入的数据的情况下，怎么破？

Question

用x,y,z定义一个三维空间，x0,y0,z0代表初始球的三维，当这个球以vx,vy,yz的速度前进，然后撞到一个边的时候，产生了另一个点(x1,y1,z1 坐标)，从x0,y0,z0到x1,y1,z1之前的距离是L0,然后x1y1z1这个点继续运行又撞到另一边的时候产生第二个点（x2，y2，z2）。n代表撞到边框的次数，编个程序求出每次撞到边时产生的点的三维坐标（例 x1,y1,z1），和每次2点之间的距离（例 L0）。n=10次

Answer 1

/*Ball.h:定义结构体和BALL相关的函数*/#ifndef _BALL_VC_SUPER_ADMI_2009_12_13_INCLUDE_#define _BALL_VC_SUPER_ADMI_2009_12_13_INCLUDE_typedef struct tagPOINT3D //3D坐标系{float x;float y;float z;}POINT3D;typedef struct tagBALL //球{POINT3D cur_coor;POINT3D speed;float radius;}BALL;typedef struct tagBOX //球的长方体运动场所,中空{POINT3D angle_coor[8]; //坐标,从下往上,顺时针float length;float width;float height;}BOX;void init_box(BOX *mybox,POINT3D origi_coor,POINT3D LWH){int i;mybox->height=LWH.x;mybox->width=LWH.y;mybox->height=LWH.z;for(i=0;i<8;i++)mybox->angle_coor[i]=origi_coor;mybox->angle_coor[1].x=origi_coor.x+LWH.x;mybox->angle_coor[2].x=origi_coor.x+LWH.x;mybox->angle_coor[2].y=origi_coor.y+LWH.y;mybox->angle_coor[3].y=origi_coor.y+LWH.y;for(i=4;i<8;i++)mybox->angle_coor[i].z=origi_coor.z+LWH.z;mybox->angle_coor[5].x=origi_coor.x+LWH.x;mybox->angle_coor[6].x=origi_coor.x+LWH.x;mybox->angle_coor[6].y=origi_coor.y+LWH.y;mybox->angle_coor[7].y=origi_coor.y+LWH.y;}void move_in_box(BALL* myball,BOX mybox) //匀速运动{myball->cur_coor.x+=myball->speed.x;myball->cur_coor.y+=myball->speed.y;myball->cur_coor.z+=myball->speed.z;}void hit_wall(BALL* myball,POINT3D dir) //撞墙{myball->speed.x*=dir.x;myball->speed.y*=dir.y;myball->speed.z*=dir.z;}int coll_dete_rad_ign(BALL* myball,BOX mybox) //检测(忽略半径){POINT3D dir;dir.x=1;dir.y=1;dir.z=1;if(myball->cur_coor.x<=mybox.angle_coor[0].x ||myball->cur_coor.x>=mybox.angle_coor[6].x)dir.x=-1;if(myball->cur_coor.y<=mybox.angle_coor[0].y ||myball->cur_coor.y>=mybox.angle_coor[6].y)dir.y=-1;if(myball->cur_coor.z<=mybox.angle_coor[0].z ||myball->cur_coor.z>=mybox.angle_coor[6].z)dir.z=-1;if(dir.x==-1 ||dir.y==-1 ||dir.z==-1){hit_wall(myball,dir);return 1;}return 0;}#endif//BALL.H文件结束/*Ball.c：测试代码*/#include "Ball.h"#include <stdio.h>int main(void){POINT3D origi;POINT3D LWH;BOX mybox;BALL myball;int i;origi.x=0;origi.y=0;origi.z=0;printf("矩形空间尺寸：");scanf("%f%f%f",&LWH.x,&LWH.y,&LWH.z);printf("球的初始坐标：");scanf("%f%f%f",&myball.cur_coor.x,&myball.cur_coor.y,&myball.cur_coor.z);printf("球的速度：");scanf("%f%f%f",&myball.speed.x,&myball.speed.y,&myball.speed.z);/* LWH.x=10;LWH.y=10;LWH.z=10;myball.cur_coor.x=5;myball.cur_coor.y=5;myball.cur_coor.z=5;myball.speed.x=0.2;myball.speed.y=0.5;myball.speed.z=1;*/i=0;init_box(&mybox,origi,LWH);printf("\n相关信息如下：\n");printf("矩形空间尺寸--L:%f,W:%f,H:%f\n",LWH.x,LWH.y,LWH.z);printf("球的初始坐标--X:%f,Y:%f,Z:%f\n",myball.cur_coor.x,myball.cur_coor.y,myball.cur_coor.z);printf("球的初始速度--X:%f,Y:%f,Z:%f\n",myball.speed.x,myball.speed.y,myball.speed.z);printf("碰撞点坐标如下：\n");while(i<10){if(coll_dete_rad_ign(&myball,mybox)==1){i++;printf("%f,%f,%f\n",myball.cur_coor.x,myball.cur_coor.y,myball.cur_coor.z);}move_in_box(&myball,mybox);}return 0;}

Answer 2

"撞到一个边的时候"如何算撞到一个边? 撞到什么的边