MergeSorting 算法不工作。继续得到一个IndexOutOFBoundsError。我相信问题可能是因为没有哨兵。leftarray当andrightarray将自身复制到时,我需要创建一个循环k,其中一个数组用完了数字,这会导致错误。我需要一些帮助来创建这个哨兵。
private static <T> void mergeSort(Comparable<? extends T>[] items, int begIndx, int endIndx) {
if (items.length > 1) {
int midIndx = items.length / 2;
@SuppressWarnings("unchecked")
T[] left = (T[]) new Object[midIndx];
@SuppressWarnings("unchecked")
T[] right = (T[]) new Object[items.length - midIndx];
for (int i = 0; i < midIndx; i++) {
left[i] = (T) items[i];
}
for (int i = midIndx; i < items.length; i++) {
right[i] = (T) items[i];
}
mergeSort(items, begIndx, midIndx);
mergeSort(items, midIndx + 1, endIndx);
merge(items, begIndx, midIndx, endIndx);
}
}
@SuppressWarnings("unchecked")
private static <T> void merge(Comparable<? extends T>[] array,
int begIndx, int midIndx, int endIndx) {
int sizeOfLeft = midIndx - begIndx + 1;
int sizeOfRight = endIndx - midIndx;
/// change to generic later
@SuppressWarnings("unchecked")
T[] leftArr = (T[]) new Object[sizeOfLeft + 1];
@SuppressWarnings("unchecked")
T[] rightArr = (T[]) new Object[sizeOfRight + 1];
for (int i = 0; i < sizeOfLeft; i++) {
leftArr[i] = (T) array[begIndx + i];
}
for (int j = 0; j < sizeOfRight; j++) {
rightArr[j] = (T) array[midIndx + j + 1];
}
int i = 0;
int j = 0;
// changed to less than or equal to rather than "less than"
// this is because this is a zero based index system
// and because endeIndex is not a length but an index,
// you need to populate it.
for (int k = begIndx; k <= endIndx; k++) {
// use comparable here
if (((Integer) leftArr[i]).compareTo((Integer) rightArr[j]) <= 0) {
array[k] = (Comparable<? extends T>) leftArr[i];
i = i + 1;
}
}
}
}
我创建了一个整数数组arr = new Integer[5]。所以应该对这 5 个数字进行排序。
慕哥9229398
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