如何在激活碰撞时让我的“游戏结束”文本保持亮起？

Question

我制作了一个带有多个下落立方体的小游戏，玩家（正方形）必须避开它。我设法使碰撞起作用，但问题是每次圆形和正方形碰撞时，每次碰撞时都会显示文本。但我希望当圆形和方形第一次发生碰撞时，文本会继续显示。有什么办法吗？

import pygame

from pygame.locals import *

import os

import random

import math

import sys

import time

white = (255,255,255)

blue = (0,0,255)

gravity = 10

size =10

height = 500

width =600

varHeigth = height

ballNum = 5

eBall = []

apGame = pygame.display.set_mode((width, height))

pygame.display.set_caption("AP Project")

clock = pygame.time.Clock()

class Player(object):

  def __init__(self):

    red = (255, 0, 0)

    move_x = 300

    move_y = 400

    self.rect = pygame.draw.rect(apGame,red, (move_x, move_y, 10, 10))

    self.dist = 10

  def handle_keys(self):

    for e in pygame.event.get():

      if e.type == pygame.QUIT:

        pygame.quit();

        exit()

    key = pygame.key.get_pressed()

    if key[pygame.K_LEFT]:

      self.draw_rect(-1, 0)

    elif key[pygame.K_RIGHT]:

      self.draw_rect(1, 0)

    elif key[pygame.K_ESCAPE]:

      pygame.quit();

      exit()

    else:

      self.draw_rect(0, 0)

  def draw_rect(self, x, y):

    red = (255, 0, 0)

    black = (0, 0, 0)

    '''apGame.fill(black)'''

    self.rect = self.rect.move(x * self.dist, y * self.dist);

    pygame.draw.rect(apGame, red , self.rect)

    pygame.display.update()

  def draw(self,surface):

    red = (255, 0, 0)

    move_x = 300

    move_y = 400

    pygame.draw.rect(apGame, red, (move_x, move_y, 10, 10))

#The game over text here 

def show_go_screen():

  pygame.font.init()

  myfont = pygame.font.SysFont("Comic Sans MS", 30)

  label = myfont.render("Game Over", 1, red)

  apGame.blit(label, (300,100))

def instuct():

  pygame.font.init()

  myfont = pygame.font.SysFont("Comic Sans MS", 15)

  label = myfont.render("Avoid The Circles", 1, red)

  apGame.blit(label, (250,450))

Answer 1

每当您希望功能只运行一次时，您应该在该函数外部添加一个检查以确保该函数内的代码只运行一次。这是使用您的代码的示例。collidedOnce = Falseif player.rect.colliderect(ball_rect):    if(collidedOnce == False):        collidedOnce = True #This makes the code only run once since it's setting this variable to be true within the condition        #game_over = True        show_go_screen()        eBall[i][1] += 5        if eBall[i][1] > height:            y = random.randrange(-50, -10)            eBall[i][1] = y            x = random.randrange(0, width)            eBall[i][0] = x        instuct()        player.handle_keys()        pygame.display.flip()        clock.tick(30)希望这可以帮助