我正在创建一个应用程序,用户可以在其中发起挑战,看看谁减重最多。
有 1 个挑战表,有一个 id、user_id(fk)、weight 和 week。为了每周在前端显示它们,我制作了一个新数组。
用户控制器:
public function index()
{
$users = User::all();
// get all challanges descending
$challanges = Challange::orderBy('week', 'DESC')->get();
// make an array for every [week] that has an array with ['user' => 'weight'] in user_id order
$weightArray = array();
// how long is the list depending on amount of weeks
$startweek = 1;
$endweek = Challange::max('week');
// go through every week
for ($i = $startweek; $i <= $endweek; $i++) {
// get weight foreach user and if no value set 0
foreach ($users as $user) {
// get challange values per week
$challenge = $user->challanges()->where('week', '=', $i)->get();
// if there is a challange
if (count($challenge) > 0) {
// set a weight value for that user *!!FIX make weigt alue unique!!*
$weightArray[$i][$user->id] = $challenge[0]->weight;
}
else {
// set 0 if no weight isset
$weightArray[$i][$user->id] = 0;
}
}
}
return view('dashboard', compact('users', 'weightArray'));
}
当用户登录并按下更新时,会有一个表单提供隐藏输入 Auth::user()->id 和星期。用户必须自己输入的重量。这会返回一个请求,但现在我不知道如何匹配周和 user_id,以找到需要更新权重的 id。
挑战控制器:
public function update(Request $request)
{
$week = $request->week;
$challange = Challange::find($request->user_id)->where('week', $week);
dd($challange);
}
这将返回:错误调用成员函数 where() on null
我应该预先在数组中添加 id 吗?还是我 where('user_id', $user_id) 并在返回的数组上执行另一个 where ?
我不知道该怎么办。有人可以帮忙吗?
交互式爱情