如何将两个数组组合成一个嵌套数组？

Question

一点背景：在技术面试中被要求回答这个问题，不能，现在我想改进但找不到回答的逻辑。

## CASE 1 ##

Given Input:

const profiles = ["Bill", "Steve", "Zuck"]

const skills = 

        [["Digital Marketing","SEO","UI/UX"], 

        ["Accounting","Digital Marketing","Employer Branding"], 

        ["Accounting","UI/UX"]]

Expected Output:

    [[["Accounting"],["Steve","Zuck"]], 

    [["Digital Marketing"],["Bill","Steve"]], 

    [["Employer Branding"],["Steve"]], 

    [["SEO"],["Bill"]], 

    [["UI/UX"],["Bill","Zuck"]]]

## CASE 2 ##

Given Input:

const profiles= ["First", "Fourth", "Second", "Third"]

const skills =

        [["One","Three","Two"], 

        ["One","One three","One two"], 

        ["One two","One two three","Two"], 

        ["One","One three","One two","One two three","Three","Two"]]

Expected Output:

    [[["One"],["First","Fourth","Third"]], 

    [["One three"],["Fourth","Third"]], 

    [["One two"],["Fourth","Second","Third"]], 

    [["One two three"],["Second","Third"]], 

    [["Three"],["First","Third"]], 

    [["Two"],["First","Second","Third"]]]

非常感谢！

Answer 1

一点背景：在技术面试中被要求回答这个问题，不能，现在我想改进但找不到回答的逻辑。## CASE 1 ##Given Input:const profiles = ["Bill", "Steve", "Zuck"]const skills =         [["Digital Marketing","SEO","UI/UX"],         ["Accounting","Digital Marketing","Employer Branding"],         ["Accounting","UI/UX"]]Expected Output:    [[["Accounting"],["Steve","Zuck"]],     [["Digital Marketing"],["Bill","Steve"]],     [["Employer Branding"],["Steve"]],     [["SEO"],["Bill"]],     [["UI/UX"],["Bill","Zuck"]]]## CASE 2 ##Given Input:const profiles= ["First", "Fourth", "Second", "Third"]const skills =        [["One","Three","Two"],         ["One","One three","One two"],         ["One two","One two three","Two"],         ["One","One three","One two","One two three","Three","Two"]]Expected Output:    [[["One"],["First","Fourth","Third"]],     [["One three"],["Fourth","Third"]],     [["One two"],["Fourth","Second","Third"]],     [["One two three"],["Second","Third"]],     [["Three"],["First","Third"]],     [["Two"],["First","Second","Third"]]]

Answer 2

这是一种可能有点昂贵但输出预期结果的方法。对于您的第二个示例，此代码仍然有效，您可能需要考虑将变量重命名为更通用的名称。const profiles = ["Bill", "Steve", "Zuck"];const skills = [    ["Digital Marketing","SEO","UI/UX"],     ["Accounting","Digital Marketing","Employer Branding"],     ["Accounting","UI/UX"]];// calculate distinct skills set from skillsconst distinctSkills = skills.reduce((acc, cur) => (    acc.concat(cur.filter((v) => (!acc.includes(v))))), []).sort();const result = distinctSkills.map((distinctSkill) => {    const people = [];    // for each distinct skill, build the right people array    // based on skills and profiles    skills.forEach((skillSet, index) => {        if (skillSet.includes(distinctSkill)) {            people.push(profiles[index]);        }    });    return [[distinctSkill]].concat([people]);});console.log(result);

Answer 3

const profiles = ["Bill", "Steve", "Zuck"];const skills = [  ["Digital Marketing", "SEO", "UI/UX"],  ["Accounting", "Digital Marketing", "Employer Branding"],  ["Accounting", "UI/UX"]];const combine = (profiles, skills) => {  const indexMap = {};  const output = [];  let index = 0;  //create array of skills and track indexes  skills.forEach(arr => {    arr.forEach(skill => {      if (!indexMap[skill]) {        indexMap[skill] = index.toString();        output.push([          [skill],          []        ])        index++;      }    })  })  //populate secondary arrays using indexmap for reference  profiles.forEach((profile, index) => {    skills[index].forEach(skill => {      let i = indexMap[skill];      output[i][1].push(profile);    })  })  //sort names incase not alphabetical  output.forEach(output => {    output[1].sort((a, b) => a[0] > b[0] ? 1 : -1);  })  // //sort skills incase not alphabetical  return output.sort((a, b) => a[0] > b[0] ? 1 : -1);}console.log(combine(profiles, skills))

Answer 4

您可以首先将所有技能名称收集到一个 Map 中，以这些名称为键，每个名称都有一个关联的空数组作为值。然后再次迭代该数据以将相应的名称推送到这些数组中。然后将这些数组从地图中取出，并在其自己的数组中以技能名称作为前缀。可选择按技能排序。const profiles = ["Bill", "Steve", "Zuck"];const skills = [["Digital Marketing","SEO","UI/UX"], ["Accounting","Digital Marketing","Employer Branding"], ["Accounting","UI/UX"]];let map = new Map(skills.flatMap(row => row.map(s => [s, []])));skills.forEach((row, i) => row.forEach(s => map.get(s).push(profiles[i])));let result = Array.from(map.entries(), ([k,v]) => [[k], v])                  .sort((a, b) => a[0][0].localeCompare(b[0][0]));console.log(result);