Django REST用数据上传多个文件

Question

我正在尝试创建一个接受（键/值）数据和多个文件的端点。用户可以serial连同他的请求一起发送多个文件。上传的文件必须保存FileModel在RequestModel. 问题是当我发送RequestSerializer无法解决的请求时files，我收到有关缺少该files字段的错误。

#tests.py

def test_create_request_with_files(self):

    with tempfile.NamedTemporaryFile() as file:

        file.write(b"SomeFakeData")

        file.seek(0)

        request = {

            'files': [file],

            'serial': "SomeSerial",

        }

        res = self.client.post(

            '/CreateRequest/', request, format='multipart')

        print(res.data)

        self.assertEqual(res.status_code, status.HTTP_201_CREATED)

#---------------------------------------------------------------------------

# models.py

class FileModel(models.Model):

    file = models.FileField(upload_to='upload_files')

class RequestModel(models.Model):

    serial = models.CharField(max_length=100)

    files = models.ManyToManyField('FileModel', blank=True)

    def __str__(self):

        return str(self.id)

#---------------------------------------------------------------------------

# serializers.py

class FileSerializer(serializers.ModelSerializer):

    class Meta:

        model = FileModel

        fields = '__all__'

        read_only_fields = ('id',)

class RequestSerializer(serializers.ModelSerializer):

    files = FileSerializer(many=True)

    def create(self, validated_data):

        files = validated_data.pop('files')

        request_model = RequestModel.objects.create(**validated_data)

        for file in files:

            file_model = FileModel.objects.create(file=file)

            request_model.files.add(file_model)

        request_model.save()

        return request_model

    class Meta:

        model = RequestModel

        fields = '__all__'

        read_only_fields = ('id')

#---------------------------------------------------------------------------

#views.py

class RequestList(generics.ListCreateAPIView):

    queryset = RequestModel.objects.all()

    serializer_class = RequestSerializer

    parser_classes = (FormParser, MultiPartParser)

Answer 1

这不是 django 的问题。使用时不能传递对象multipart/form-data。列表将转换为[object Object]字符串。而是尝试：file1等file2...我会使用动态解析器，例如：        count = 1        files = []        f = request.data.get('file{}'.fomat(count))        while f is not None:            files.append(f)            count += 1            f = request.data.get('file{}'.fomat(count))