我有两个清单
List A (CG300019159, CG300018158, FS300076458)
List B Returns grouped lists like below
{
"pallet_identifier": "CG300018158",
"shipment_items": [
{
"sku": "10366960",
"stock_qty": 12,
"description": "MOTHERCARE CREAM BABYGROW W/HAT"
},
{
"sku": "10346788",
"stock_qty": 1,
"description": "KIT 7PC ESS CREW NECK CARDIGAN SKY BLUE"
}
]
},
"pallet_identifier": "CG300018187",
"shipment_items": [
{
"sku": "10366960",
"stock_qty": 12,
"description": "MOTHERCARE CREAM BABYGROW W/HAT"
},
{
"sku": "10346788",
"stock_qty": 1,
"description": "KIT 7PC ESS CREW NECK CARDIGAN SKY BLUE"
}
]
},
我想使用属性pallet_identifier 从列表B 中删除托盘及其内容。
尝试如下
entity = new List<GoodInWarehouseBM>((from consighdrs in mi9db.consighdrs
join consigdests in mi9db.consigdests on consighdrs.consignment equals consigdests
.consignment
join consigliness in mi9db.consiglines on consigdests.condestint equals consigliness
.condestint
join productcodess in mi9db.productcodes on consigliness.varint equals productcodess.varint
join products in mi9db.products on productcodess.prodint equals products.prodint
where consigdests.destination == storeId && consighdrs.status == "T" && consighdrs.warehouse == "900"
group new { consigdests, productcodess, consigliness, products } by consigdests.consignment into grp
select new GoodInWarehouseBM
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