将项目从一个列表移动到另一个列表并删除字符串的某些部分

Question

我有这个带有 ID 和标题的列表

myemails = [12345, 56789, 456789, 54321, 98765, 'Sample Title: Title number one', 'Sample Title: Title number two', 'Sample Title: Title number three', 'Sample Title: Title number four', 'Sample Title: Title number five']

我正在寻找一种方法将此列表拆分为两个单独的列表，其中一个仅存储 ID，另一个标题中没有字符串的“示例标题：”部分：

myemailId = [12345, 56789, 456789, 54321, 98765]

myemailTitle = ['Title number one', 'Title number two', 'Title number three', 'Title number four', 'Title number five']

到目前为止我的代码：

from collections import defaultdict

myemails = [12345, 56789, 456789, 54321, 98765, 'Sample Title: Title number one', 'Sample Title: Title number two', 'Sample Title: Title number three', 'Sample Title: Title number four', 'Sample Title: Title number five'] 

d = defaultdict(myemails)

for x in myList:

   d[type(x)].append(x)

emailId = print d[int]

emailTitle = print  d[str]

但是它会引发此错误：

TypeError: first argument must be callable or None

有人可以帮我吗？提前致谢！

Answer 1

利用：myemailid = [item for item in myemails if str(item).isdigit()]myemailtitle = [item.replace("Sample Title: ", "") for item in myemails if not str(item).isdigit()]print(myemailid)print(myemailtitle)这打印：[12345, 56789, 456789, 54321, 98765]['Title number one', 'Title number two', 'Title number three', 'Title number four', 'Title number five']

Answer 2

您的代码中有几个问题defaultdict应该用类型初始化，但你用myemails而不是初始化它list您将结果分配给print变量（print返回None）试试这个：myemails = [12345, 56789, 456789, 54321, 98765, 'Sample Title: Title number one', 'Sample Title: Title number two', 'Sample Title: Title number three', 'Sample Title: Title number four', 'Sample Title: Title number five'] ids = []titles = []for x in myemails:    if type(x) == int:        ids.append(x)      elif type(x) == str:        titles.append(x)    else:        print("unsupported type {} of {}".format(type(x),x))print(ids)print(titles)