如果 id 有特定的类，使用 JS/jQuery Show() + Hide() 排序？
我正在尝试编写一个代码，根据它们的类名对 div 进行排序，并带有切换 show(); 的按钮；如果该类存在但 hide(); 如果该类不存在。我没有收到任何错误，但代码不想按照我认为我告诉它的方式工作？当您在我的预览中单击按钮时，它会隐藏具有类名的 id，而对没有类名的 id 则不执行任何操作。
CSS
<html>
<头部>
<title>排序</title>
<link rel="stylesheet" type="text/css" href="assets/css/style.css">
<script type="text/javascript" src="assets/js/jquery.js"></script>
<script type="text/javascript" src="assets/js/jquery-ui.js"></script>
</head>
<正文>
<div id="sort-box"><div id="button-wrap">
<button id="everyone" class="sort-button active">所有人</button>
<button id="lions" class="sort-button">狮子</button>
<button id="tigers" class="sort-button">老虎</button>
<button id="bears" class="sort-button">熊</button>
<textarea id="search" class="sort-button" placeholder="search"></textarea></div>
<div class="sort-hold">
<div id="member" class="lions all">会员名 - 狮子</div>
<div id="member" class="tigers all">会员名-老虎</div>
<div id="member" class="bears all">会员名-熊</div>
</div>
</div>
<script type="text/javascript" src="assets/js/main.js"></script>
</正文>
</html>
JS
var btnWrap = document.getElementById("button-wrap");
// 获取容器内所有 class="btn" 的按钮
var btns = btnWrap.getElementsByClassName("排序按钮");
// 循环遍历按钮并将活动类添加到当前/单击的按钮
for (var i = 0; i < btns.length; i++) {
btns[i].addEventListener("点击", function() {
var current = document.getElementsByClassName("active");
current[0].className = current[0].className.replace("active", "");
this.className += "活跃";
});
}
$("#everyone").click(sortEveryone);
功能排序所有人（）{
console.log("按钮点击了！")
$("#member").show();
};
$("#lions").click(sortOne);
函数 sortOne() {
console.log("按钮点击了！")
if($("#member").hasClass(".lions")){
$("#member").show();
} 别的 {
$("#member").hide();
}
};
狐的传说2回答
-
开满天机
您可以使用更通用的方法来执行此操作，对所有按钮使用一键式侦听器，并检查事件发生的那个的 id 并做出相应的反应const $items = $('.sort-hold').children()$('.sort-button').click(function(){ // remove active class from other buttons $('.sort-button.active').removeClass('active'); // make this button active $(this).addClass('active'); // hide/show logic if(this.id === 'everyone'){ $items.show() }else{ $items.hide().filter('.' + this.id).show(); }})<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script><div id="sort-box"><div id="button-wrap"><button id="everyone" class="sort-button active">everyone</button><button id="lions" class="sort-button">lions</button><button id="tigers" class="sort-button">tigers</button><button id="bears" class="sort-button">bears</button></div><div class="sort-hold"> <div class="lions all">member name - lion</div> <div class="tigers all">member name - tiger</div> <div class="bears all">member name - bear</div></div></div> -
慕勒3428872
这是我的解决方案。将每个人都添加到每个人 btn 并将 sort-hold成员替换为类名而不是id<div id="sort-box"><div id="button-wrap"><button id="everyone" class="sort-button everyone active">everyone</button><button id="lions" class="sort-button">lions</button><button id="tigers" class="sort-button">tigers</button><button id="bears" class="sort-button">bears</button><textarea id="search" class="sort-button" placeholder="search"></textarea></div><div class="sort-hold"> <div class="lions all member">member name - lion</div> <div class="tigers all member">member name - tiger</div> <div class="bears all member">member name - bear</div></div></div> <script type="text/javascript" src="https://files.jcink.net/uploads2/colourcoded/jquery.js"></script> <script type="text/javascript" src="https://files.jcink.net/uploads2/colourcoded/jquery_ui.js"></script>将#member修复为.member.member { margin: 10px; width: calc(100% - 70px); height: 50px; line-height: 50px; padding: 0px 25px; text-transform: uppercase; font-family: arial; background: #fff; font-size: 10px; outline: 1px solid #ddd; outline-offset: -1px;}// Get the container elementvar btnWrap = document.getElementById("button-wrap");// Get all buttons with class="btn" inside the containervar btns = btnWrap.getElementsByClassName("sort-button");// Loop through the buttons and add the active class to the current/clicked buttonfor (var i = 0; i < btns.length; i++) { btns[i].addEventListener("click", function() { var current = document.getElementsByClassName("active"); current[0].className = current[0].className.replace(" active", ""); this.className += " active"; });}$("#everyone").click(sortEveryone);function sortEveryone() { console.log("button clicked!") $(".member").show();}// add activeBtn function for all btns except .everyonefor (var btn of btns) { $(btn).hasClass("everyone") == false ? btn.addEventListener("click", activeBtn) : "";}function activeBtn(e) { let targetId = e.target.id; let members = $(".member"); // if the member class has the same name as the btn id, show it else hide it for (var member of members) { $(member).hasClass(targetId) ? $(member).show() : $(member).hide(); }}我已将 #member 更改为 .member，拥有多个具有相同 ID 的元素并不是一个好方法。我已经为每个人添加了.everyone以使其更易于处理。
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相关分类
JavaScript