不再支持带时间戳的整数和整数数组的加法/减法。而不是添加/减去`n`

Question

我正在使用 pytrends 库来提取谷歌趋势，我收到以下错误：

不再支持带时间戳的整数和整数数组的加法/减法。而不是加/减n，使用n * obj.freq

timeframes = []

datelist = pd.date_range('2004-01-01', '2018-01-01', freq="AS")

date = datelist[0]

while date <= datelist[len(datelist)-1]:

    start_date = date.strftime("%Y-%m-%d")

    end_date = (date+4).strftime("%Y-%m-%d")

    timeframes.append(start_date+' '+end_date)

    date = date+3

Answer 1

您不能将日期和数字相加，date+4因为谁知道这是哪个单位4h，, 4d, ...？您可以使用datetime.timedelta，如果您的意思是，这是一个示例daysfrom datetime import timedeltaend_date = (date + timedelta(days=4)).strftime("%Y-%m-%d")# ...date = date + timedelta(days=3)

Answer 2

既然你已经在使用 Pandas，为什么还要麻烦导入其他东西呢？你可以做：import pandas as pd&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; # your codedate = pd.date_range('2004-01-01', '2018-01-01', freq="AS")&nbsp; &nbsp; # your codefreq = 'D'&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;# 'H' for hours, etc.date = date + pd.Timedelta(3, unit=freq)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;# Perform the actionprint(date)输出（与azro的答案相同）：DatetimeIndex(['2004-01-04', '2005-01-04', '2006-01-04', '2007-01-04',&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;'2008-01-04', '2009-01-04', '2010-01-04', '2011-01-04',&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;'2012-01-04', '2013-01-04', '2014-01-04', '2015-01-04',&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;'2016-01-04', '2017-01-04', '2018-01-04'],&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; dtype='datetime64[ns]', freq=None)使用这种方法的另一个原因是，您可能会发现自己处于向日期动态添加内容的情况，例如在方法内部，并且您将单位作为参数传递。如果您使用的是timedelta(days=3)，您将无法更改其他任何内容（小时、分钟等），但只有几天！