如何在 python 的方法中使用属性函数？

Question

我尝试编写代码 2 来做与代码 1 相同的事情。但是，代码 2 不起作用。为什么？如何在 python 的方法中使用属性函数？

（代码 1）

class Spam:

    def __init__(self, is_less_sodium):

        self.__is_less_sodium = is_less_sodium

    def __getter(self):

        return self.__is_less_sodium

    is_less_sodium = property(__getter)

my_spam = Spam(False)

print(my_spam.is_less_sodium)

########## Result ##########

# False

（代码 2）

class Spam:

    def __init__(self, is_less_sodium):

        self.__is_less_sodium = is_less_sodium

        Spam.is_less_sodium = property(self.__getter)

    def __getter(self):

        return self.__is_less_sodium

my_spam = Spam(False)

print(my_spam.is_less_sodium)

########## Result ##########

# Traceback (most recent call last):

#   File "code2.py", line 10, in <module>

#     print(my_spam.is_less_sodium)

# TypeError: __getter() takes 1 positional argument but 2 were given

我理解代码1中的返回值property(__getter)是赋值给的is_less_sodium，这是一个类变量Spam。但是，这种理解似乎是错误的。

Answer 1

class Spam:&nbsp; &nbsp; def __init__(self, is_less_sodium):&nbsp; &nbsp; &nbsp; &nbsp; self.__is_less_sodium = is_less_sodium&nbsp; &nbsp; &nbsp; &nbsp; Spam.is_less_sodium = property(Spam.__getter,)&nbsp; &nbsp; def __getter(self):&nbsp; &nbsp; &nbsp; &nbsp; return self.__is_less_sodiummy_spam = Spam(False)print(my_spam.is_less_sodium)您可以使用该语法，但您还必须从类级别引用该函数，而不是实例函数。装饰器语法更简洁。class Spam:&nbsp; &nbsp; def __init__(self, is_less_sodium):&nbsp; &nbsp; &nbsp; &nbsp; self.__is_less_sodium = is_less_sodium&nbsp; &nbsp; @property&nbsp; &nbsp; def is_less_sodium(self):&nbsp; &nbsp; &nbsp; &nbsp; return self.__is_less_sodium&nbsp; &nbsp; @is_less_sodium.setter&nbsp; &nbsp; def set_is_less_sodium(self):&nbsp; &nbsp; &nbsp; &nbsp; self.__is_less_sodiummy_spam = Spam(False)print(my_spam.is_less_sodium)my_spam.is_less_sodium = Trueprint(my_spam.is_less_sodium)