根据登录名显示输入 - PHP

Question

我有一个带有一些输入的表单，当我登录系统时，我想为每个不同的登录只显示1个输入，我想使用IF和OTHER，但我不知道如何使用它，有人可以帮助我吗？

我正在尝试这样

<?php 

$login = $_SESSION['login'];

$senha = $_SESSION['senha'];

$sql = "SELECT * FROM login WHERE login ='$login' AND senha = '$senha'";

$resultado = mysqli_query($link, $sql);

while ($cont = mysqli_fetch_array($resultado)) 

{  

    $class = $cont['class'];

}

$codigo_relatorio = $_GET['codigo_relatorio'];

$sql = mysqli_query($link, "SELECT * FROM relatorio WHERE codigo_relatorio = '$codigo_relatorio' ");

while ($cont = mysqli_fetch_array($sql)) {

   if ($class == "adm") {

        echo '

          <div class="form-group">

          <label for="file-multiple-input" class=" form-control-label"> <b>Educação Física - Arquivo:</b></b></label>

          <a style='color: Blue' href="uploads/uploadsed/<?php echo $cont['relatorio_educacao_fisica'];?>"><?php echo $cont['relatorio_educacao_fisica'];?></a>

          <input type="file" id="file-multiple-input" name="fileed" multiple="" class="form-control-file" >

          </div>';

}

?>  

示例：如果您已登录（educacao_fisica），则只能看到educacao_fisica输入...

它继续显示给所有登录名...

Answer 1

它的工作原理，我把它放在页面的开头：：<?php&nbsp;&nbsp;// Iniciando a sessãosession_start();if((!isset ($_SESSION['login']) == true) and (!isset ($_SESSION['senha']) == true)){&nbsp; unset($_SESSION['login']);&nbsp; unset($_SESSION['senha']);&nbsp; header('location:login.php');&nbsp; }$logado = $_SESSION['login'];?> .....谢谢大家的提示！