如何设置命令以通过txt文件DJANGO填充DJANGO数据

Question

感谢您抽出宝贵时间接受采访：

我得到了一个模型，它必须填充3个txt文档，每个文档有40行。该命令应打开每个取行，设置对象，保存它，然后在40范围内再次调用：

我能够调用它40次，尽管我40个正在使用相同的最后一行，我如何在txt文件上设置计数以在再次调用时转到下一行？我应该设置一个分割来获取行作为列表吗？并像列表索引一样设置行？list[counter]

models.py：

class MP4 (models.Model):

    nome = models.CharField(blank=True, max_length=100)

    url = models.URLField(blank=True, max_length=300)

    imagem = models.ImageField(blank=True, upload_to='')

    artista = models.CharField(blank=True, max_length=100, default='Unknown')

seeder.py（命令）：

class Command(BaseCommand):

    file_name = ['nome.txt', 'artista.txt', 'url.txt']

    @classmethod

    def handle(cls, *args, **kwargs):

        counter = 0

        for row in range(40):

            counter += 1 

            with open(cls.file_name[0]) as file:

                for linha in file:

                    nome = linha

            with open(cls.file_name[1]) as file:

                for linha in file:

                    artista = linha

            with open(cls.file_name[2]) as file:

                for linha in file:

                    url = linha

            row = MP4(

                nome=nome,

                url=url,

                artista=artista,

                id=MP4.objects.latest('id').id + 1

                )

            row.save()

名词.txt：

Somewhere over the Rainbow

ocean drive

Michael Jackson - Billie Jean ( cover by J.Fla )

...

网址.txt：

https://www.youtube.com/watch?v=V1bFr2SWP1I&list=RDV1bFr2SWP1I&start_radio=1

https://www.youtube.com/watch?v=KDxJlW6cxRk&list=RDVHoT4N43jK8&index=19

https://www.youtube.com/watch?v=J1AdPY73qxo

...

艺术家.txt

gordinho havaiano

duke dumont

Michael Jackson

...

Answer 1

我想你可以一起打开所有3个文件，并用zip循环它。file_name = ['nome.txt', 'artista.txt', 'url.txt']with open(file_name[0]) as file1, open(file_name[1]) as file2, open(file_name[2]) as file3:    for data in zip(file1, file2, file3):        nome, artista, url = data         row = MP4(            nome=nome,            url=url,            artista=artista,            id=MP4.objects.latest('id').id + 1            )        row.save()