烧瓶形式选择字段
我的 app.py 看起来像这样：
from flask import Flask,render_template,url_for,request
from flask_bootstrap import Bootstrap
from wtforms import SelectField
from flask_wtf import FlaskForm
app = Flask(__name__)
Bootstrap(app)
def Form(FlaskForm):
panel_brand = SelectField('Panel Brand',choices=[('tr','trina'),('lo','longi'), ('ph','phono'), ('leap','leapton')])
mounting = SelectField('Mounting',choices=[('tr','trina'),('lo','longi'), ('ph','phono'), ('leap','leapton')])
inverter = SelectField('inverter',choices=[('Fronius10','Fronius 10'),('Fronius5','Fronius 5'), ('huawei6','huawei 6'), ('huawei8','huawei 8') , ('SolarEdge125','SolarEdge 12,5')])
order_fulfillment = SelectField('orderfulfillment',choices=[('all3','Panels + inverter + mounting'),('Panels','Panels'),('panelsinv','Panels + Inverter'),('installer','By Installer')])
@app.route('/', methods=['GET','POST'])
def index():
form = Form(FlaskForm)
return render_template('index.html', form=form)
if __name__ == '__main__':
app.run(debug=True)
我的索引.html看起来像这样
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>Document</title>
</head>
<body>
<form method="POST">
{{ form.csrf_token }}
{{ form.panel_brand }}
{{ form.mounting }}
{{ form.inverter }}
{{ form.order_fulfillment }}
<input type="submit">
</form>
</body>
</html>
当我运行 app.py 文件时，它只显示提交按钮，而不是预期的下拉列表，，，， - 具有后续值。我想我在函数中缺少一些调用ID？我不确定如何以正确的语法做到这一点。任何人都可以帮我吗？panel_brandmountinginverterorder_fulfillmentindex()
守着星空守着你2回答
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长风秋雁
您的代码有一个函数，它需要有一个类。改变def Form(FlaskForm):...form = Form(FlaskForm)自class Form(FlaskForm)...form = Form(request.form)和 -
慕勒3428872
您的声明似乎正在对另一个对象进行子类化。form尝试：def index(): form = Form(request.form)
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