如果日期匹配，则将项推送到数组中 - 脚本/类型脚本

Question

做空数组以显示它们相对于日期，就像我所做的那样 - 徒步旅行，在2020-05-10购物和徒步旅行，在2020-05-10上足球和其他日期类似。

 const items = [

 {title: 'Hiking', date: new Date('2020-05-10')},

 {title: 'Shopping', date: new Date('2020-05-10')},

 //

 {title: 'Hiking', date: new Date('2020-05-22')},

 {title: 'Football', date: new Date('2019-05-22')},

 //

 {title: 'Football', date: new Date('2020-05-28')},

 {title: 'Hiking', date: new Date('2020-05-28')},

 {title: 'Cricket', date: new Date('2020-05-28')},

];

Answer 1

您需要使用 。reduce()var items = [ {title: 'Hiking', date: new Date('2020-05-10')}, {title: 'Shopping', date: new Date('2020-05-10')},{title: 'Hiking', date: new Date('2020-05-22')}, {title: 'Football', date: new Date('2020-05-22')}, {title: 'Football', date: new Date('2020-05-28')}, {title: 'Hiking', date: new Date('2020-05-28')}, {title: 'Cricket', date: new Date('2020-05-28')}];var result = items.reduce((acc, {title, date})=>{    dateKey = new Date(date).toISOString().slice(0,10);    acc[dateKey] = acc[dateKey] || [];    acc[dateKey].push({title});    return acc;},{});console.log(result);

Answer 2

试试这个let items = [      {title: 'Hiking', date: new Date('2020-05-10')},      {title: 'Shopping', date: new Date('2020-05-10')},      {title: 'Hiking', date: new Date('2020-05-22')},      {title: 'Football', date: new Date('2019-05-22')},      {title: 'Football', date: new Date('2020-05-28')},      {title: 'Hiking', date: new Date('2020-05-28')},      {title: 'Cricket', date: new Date('2020-05-28')},     ];    items.sort(function(a,b){      return a.date - b.date;    });    console.log(items);