如何在不合并对象属性的情况下推送对象数组以创建新数组？

Question

我正在尝试将循环输出保存到一个数组中。如果我控制台.log（arr2），我得到了我想要的结果，但在多个数组中。我想把所有这些东西都放在一个数组中。当我尝试使用 .push 时，所有数组都会产生相同的值。

也许我可以以其他方式做到这一点，但我不知道该怎么做。

    let b = {};

    let arr3 = [];

    let arr1 = [{value1: 123, value2: 34, value3: 90, value4: 23, value5: 32},{value1: 10, value2: 09, value3: 54, value4: 32, value5: 311}];

    for (let a = 0; a <=4; a++){

       b = {"value1": a*a, "value3": a+12, "value4": a/2};

       arr2 = arr1.map(function(record){

       record.value1 = b.value1;

       record.value3 = b.value3;

       record.value4 = b.value4;

       return record;

       })

       // console.log(arr2);

       arr3.push(arr2);

}

console.log(arr3);

这就是我用.push完成的，这不是我想要的。

  [

  { value1: 0, value2: 34, value3: 12, value4: 0, value5: 32 },

  { value1: 0, value2: 9, value3: 12, value4: 0, value5: 311 }

]

[

  { value1: 1, value2: 34, value3: 13, value4: 0.5, value5: 32 },

  { value1: 1, value2: 9, value3: 13, value4: 0.5, value5: 311 }

]

[

  { value1: 4, value2: 34, value3: 14, value4: 1, value5: 32 },

  { value1: 4, value2: 9, value3: 14, value4: 1, value5: 311 }

]

[

  { value1: 9, value2: 34, value3: 15, value4: 1.5, value5: 32 },

  { value1: 9, value2: 9, value3: 15, value4: 1.5, value5: 311 }

]

[

  { value1: 16, value2: 34, value3: 16, value4: 2, value5: 32 },

  { value1: 16, value2: 9, value3: 16, value4: 2, value5: 311 }

]

当我控制台.log（arr2）在for循环中时，我得到了几乎我想要的东西，想要的结果，但不是在单个数组中。

   [

  { value1: 0, value2: 34, value3: 12, value4: 0, value5: 32 },

  { value1: 0, value2: 9, value3: 12, value4: 0, value5: 311 }

]

[

  { value1: 1, value2: 34, value3: 13, value4: 0.5, value5: 32 },

  { value1: 1, value2: 9, value3: 13, value4: 0.5, value5: 311 }

]

[

  { value1: 4, value2: 34, value3: 14, value4: 1, value5: 32 },

  { value1: 4, value2: 9, value3: 14, value4: 1, value5: 311 }

]

[

  { value1: 9, value2: 34, value3: 15, value4: 1.5, value5: 32 },

  { value1: 9, value2: 9, value3: 15, value4: 1.5, value5: 311 }

]

[

  { value1: 16, value2: 34, value3: 16, value4: 2, value5: 32 },

  { value1: 16, value2: 9, value3: 16, value4: 2, value5: 311 }

]

Answer 1

这是因为对象通过引用工作。这应该有效： 替换这个：&nbsp;arr2 = arr1.map(function(record){&nbsp; &nbsp;record.value1 = b.value1;&nbsp; &nbsp;record.value3 = b.value3;&nbsp; &nbsp;record.value4 = b.value4;&nbsp; &nbsp;return record;&nbsp; &nbsp;})通过您的代码中的这个：&nbsp;arr2 = arr1.map(function(record) {const tempRecord = {...record}tempRecord.value1 = b.value1;tempRecord.value3 = b.value3;tempRecord.value4 = b.value4;return tempRecord;})你可以通过这样做来完成最终结果：arr3.flat（）;