在列表列表中使用筛选器和 lambda

Question

我使用列表的列表。这些列表中的每一个都是相同的 - 它们包含标题，url和一些额外的统计信息（始终以相同的顺序）。

我想创建一个函数 ，它采用所需的标题并返回整个列表（带有标题，url和统计信息）。这是我的尝试find_title

def find_title(title, ls):

    return(list(filter(lambda x: x[0] == title, ls)))

但是它不起作用，它不返回任何内容。这可能是因为仅表示大列表中的第一个元素。如何修复？x[0]

编辑。这是ls的一部分：

[['Der Vagabund und das Kind (1921)',

  'http://www.imdb.com/title/tt0012349/',

  0,0,0,0,0,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],

 ['Goldrausch (1925)',

  'http://www.imdb.com/title/tt0015864/',

  0,0,1,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],

 ['Metropolis (1927)',

  'http://www.imdb.com/title/tt0017136/',

  0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0]]

Answer 1

您可以直接从数据帧中提取信息，如下所示：import pandas as pddf = pd.DataFrame([['Der Vagabund und das Kind (1921)',  'http://www.imdb.com/title/tt0012349/',  0,0,0,0,0,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0], ['Goldrausch (1925)',  'http://www.imdb.com/title/tt0015864/',  0,0,1,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0], ['Metropolis (1927)',  'http://www.imdb.com/title/tt0017136/',  0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0]])print(df[df[0] =='Goldrausch (1925)'])