Python字典：返回列表或字符串中的第一个值
我有一个字典列表，其中我试图使键“Username”的值成为新字典中的键，并将随后的键值对作为新字典中的“用户名”键的字典值。
其中一项检查涉及从列表中返回第一个元素（如果该值为列表），否则返回键的字符串值。GECOSGECOS
对于前两个字典，我无法获取整个字符串。
我有以下数据：
test_list = [
{
"Username": "root",
"UID": "0",
"GECOS": "root",
"Group List": [
""
]
},
{
"Username": "daemon",
"UID": "1",
"GECOS": "daemon",
"Group List": [
""
]
},
{
"Username": "hplip",
"UID": "118",
"GECOS": [
"HPLIP system user",
"",
"",
""
],
"Group List": [
""
]
},
{
"Username": "speech-dispatcher",
"UID": "111",
"GECOS": [
"Speech Dispatcher",
"",
"",
""
],
"Group List": [
"pulse",
"test"
]
}
]
和以下代码：
import json
new_dict = {}
for dict_item in test_list:
for key in dict_item:
new_dict[dict_item["Username"]] = {
'UID'.title().lower(): dict_item['UID'],
'GECOS'.title(): dict_item['GECOS'][0] if isinstance(dict_item[key], list) else dict_item['GECOS'],
'Group List'.title(): [] if all('' == s or s.isspace() for s in dict_item['Group List']) else dict_item['Group List']
}
print(json.dumps(new_dict, indent=4))
其输出为：
{
"root": {
"uid": "0",
"Gecos": "r",
"Group List": []
},
"daemon": {
"uid": "1",
"Gecos": "d",
"Group List": []
},
"hplip": {
"uid": "118",
"Gecos": "HPLIP system user",
"Group List": []
},
"speech-dispatcher": {
"uid": "111",
"Gecos": "Speech Dispatcher",
"Group List": [
"pulse",
"test"
]
}
}
白猪掌柜的1回答
-
MMMHUHU
不应循环访问每个字典的键。相反，直接访问密钥，就像字典应该：import jsonnew_dict = {}for dict_item in test_list: new_dict[dict_item["Username"]] = { 'UID'.title().lower(): dict_item['UID'], 'GECOS'.title(): dict_item['GECOS'][0] if isinstance(dict_item['GECOS'], list) else dict_item['GECOS'], 'Group List'.title(): [] if all('' == s or s.isspace() for s in dict_item['Group List']) else dict_item['Group List'] }print(json.dumps(new_dict, indent=4))
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Python