计算 python 中两小时变量之间的差异

Question

我目前正在开发一个程序，该程序将计算两个时间点之间的小时数差。可变参数将始终在同一日期。所以对我来说，唯一重要的是时间。我计划使用日期时间，但如果有其他导入，我开放其他示例

    # This is just a ruff idea of how it should work, but im aware it doesn't work

    var1 = datetime.now().striftime('%H:%M')

    var2 = 14:55  # This is just an example

    vardiff = var2 - var1  # var2 is always bigger than var1

    print(vardiff)

Answer 1

似乎有一些与您的问题有关的东西已经在如何在python中找到两个日期时间对象之间的时间差？>>> import datetime>>> first_time = datetime.datetime.now()>>> later_time = datetime.datetime.now()>>> difference = later_time - first_time>>> seconds_in_day = 24 * 60 * 60datetime.timedelta(0, 8, 562000)>>> divmod(difference.days * seconds_in_day + difference.seconds, 60)(0, 8)      # 0 minutes, 8 seconds基于此，您可以通过以下方式获得小时数import datetimefirst_time = datetime.datetime.strptime('12:00', '%H:%M')later_time = datetime.datetime.now()difference = later_time - first_timehours, remainder = divmod(difference.seconds, 3600)minutes,seconds=divmod(remainder,60)对于时间增量，还有另一个有用的问题/答案：将时间详图转换为天，小时和分钟

Answer 2

您需要比较 s 而不是字符串。datetime类似的东西>>> import datetime>>> t1 = datetime.datetime.strptime('03:12', '%H:%M')>>> t2 = datetime.datetime.strptime('14:19', '%H:%M')>>> t2 - t1datetime.timedelta(0, 40020)>>> print(t2 - t1)11:07:00