我正在使用Golang gorilla / mux包,其中一个例子如下:
func main() {
var wait time.Duration
flag.DurationVar(&wait, "graceful-timeout", time.Second * 15, "the duration for which the server gracefully wait for existing connections to finish - e.g. 15s or 1m")
flag.Parse()
r := mux.NewRouter()
// Add your routes as needed
srv := &http.Server{
Addr: "0.0.0.0:8080",
// Good practice to set timeouts to avoid Slowloris attacks.
WriteTimeout: time.Second * 15,
ReadTimeout: time.Second * 15,
IdleTimeout: time.Second * 60,
Handler: r, // Pass our instance of gorilla/mux in.
}
// Run our server in a goroutine so that it doesn't block.
go func() {
if err := srv.ListenAndServe(); err != nil {
log.Println(err)
}
}()
c := make(chan os.Signal, 1)
// We'll accept graceful shutdowns when quit via SIGINT (Ctrl+C)
// SIGKILL, SIGQUIT or SIGTERM (Ctrl+/) will not be caught.
signal.Notify(c, os.Interrupt)
// Block until we receive our signal.
<-c
// Create a deadline to wait for.
ctx, cancel := context.WithTimeout(context.Background(), wait)
defer cancel()
// Doesn't block if no connections, but will otherwise wait
// until the timeout deadline.
srv.Shutdown(ctx)
// Optionally, you could run srv.Shutdown in a goroutine and block on
// <-ctx.Done() if your application should wait for other services
// to finalize based on context cancellation.
log.Println("shutting down")
os.Exit(0)
}
这似乎很简单,但我的理解是,在调用时,延迟不会运行(根据 https://gobyexample.com/exit)。我注意到有一个返回的 by ,然后被推迟。我的猜测是,如果在截止日期之前完成,这应该取消上面创建的上下文,但我不明白在最后调用时会如何发生这种情况。任何人都可以帮我看到我错过了什么吗?os.Exit()CancelFunc()context.WithTimeout()main()os.Exit()
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