如何从数组对象中删除 £ 符号并保存它？

Question

我正在为一个大学项目编写一个基本的聊天机器人。我到了用户必须通过输入金额来设置预算的地步。目前，该程序能够在用户的消息中搜索数字并正确保存。但是，当 £ 符号作为前缀时，由于邮件中包含井号，因此无法保存为整数。

这是我的代码：

//Scan the user message for a budget amount and save it.

    for (int budgetcount = 0; budgetcount < words.length; budgetcount++) 

    {

        if (words[budgetcount].matches(".*\\d+.*"))

        {

            if (words[budgetcount].matches("\\u00A3."))

            {

                words[budgetcount].replace("\u00A3", "");

                System.out.println("Tried to replace a pound sign");

                ResponsesDAO.budget = Integer.parseInt(words[budgetcount]);

            }

            else

            {

                System.out.println("Can't find a pound sign here.");

            }

        }

我以前尝试过.contains（）和其他指示它是我要删除的磅符号的方法，但我仍然得到“在这里找不到磅符号”打印出来。

如果有人可以提供建议或纠正我的代码，我将不胜感激。

Answer 1

Strings在JAVA中是不可变的。您正在替换，但从未将结果重新分配给 。words[budgetcount]更改代码中的以下行，words[budgetcount] = words[budgetcount].replace("\u00A3", "");这是另一种方法，通过使用来识别数字并编织一个仅数字字符串，该字符串以后可以解析为整数，Character.isDigit(...)代码段：private String removePoundSign(final String input) {&nbsp; &nbsp; StringBuilder builder = new StringBuilder();&nbsp; &nbsp; for (int i = 0; i < input.length(); i++) {&nbsp; &nbsp; &nbsp; &nbsp; char ch = input.charAt(i);&nbsp; &nbsp; &nbsp; &nbsp; if (Character.isDigit(ch)) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; builder.append(ch);&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }&nbsp; &nbsp; return builder.toString();}输入：System.out.println(removePoundSign("£12345"));输出：12345

Answer 2

您也可以使用方法。String.replaceAll代码片段：public class TestClass {&nbsp; &nbsp; public static void main(String[] args){&nbsp; &nbsp; &nbsp; &nbsp; //Code to remove non-digit number&nbsp; &nbsp; &nbsp; &nbsp; String budgetCount = "£34556734";&nbsp; &nbsp; &nbsp; &nbsp; String number=budgetCount.replaceAll("[\\D]", "");&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(number);&nbsp; &nbsp; &nbsp; &nbsp; //Code to remove any specific characters&nbsp; &nbsp; &nbsp; &nbsp; String special = "$4351&2.";&nbsp; &nbsp; &nbsp; &nbsp; String result = special.replaceAll("[$+.^&]",""); // regex pattern&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(result);&nbsp; &nbsp; }}输出：3455673443512