我的一些go-graphql查询的字段返回null，而其他字段恢复正常，其他类似的查询一起工作
我一直在尝试go-grapqhql，并且我已经能够成功地创建一些架构，如下所示：
type Artist struct {
ID string `json:"id,omitempty"`
Name string `json:"name"`
Type string `json:"type"`
Instrument []Instrument `json:"instrument"`
}
type Instrument struct{
Name string `json:"name"`
}
var artists = []Artist{
{
ID: "1",
Name: "Taylor Swift",
Type: "artist",
Instrument: []Instrument{
{Name:"violin"},
},
},
}
var instrumentType = graphql.NewObject(graphql.ObjectConfig{
Name: "Instrument",
Fields: graphql.Fields{
"name": &graphql.Field{
Type: graphql.String,
},
},
})
var artistType = graphql.NewObject(graphql.ObjectConfig{
Name: "Artist",
Fields: graphql.Fields{
"id": &graphql.Field{
Type: graphql.String,
},
"name": &graphql.Field{
Type: graphql.String,
},
"type": &graphql.Field{
Type: graphql.String,
},
"instrument": &graphql.Field{
Type: graphql.NewList(instrumentType),
},
},
})
但是，当我尝试用类似的结构做同样的事情时......
type Blk struct {
Header Header `json:"header,omitempty"`
Payload []Payload `json:"payload,omitempty"`
}
type Header struct {
Parent string `json:"parent,omitempty"`
Number int `json:"number,omitempty"`
Nonce int `json:"nonce,omitempty"`
Time int `json:"time,omitempty"`
Miner string `json:"miner,omitempty"`
}
type Payloads []Payloads
type Payload struct {
From string `json:"from,omitempty"`
To string `json:"to,omitempty"`
Value int `json:"value,omitempty"`
Nonce int `json:"nonce,omitempty"`
Data string `json:"data,omitempty"`
Time int `json:"time,omitempty"`
Signature string `json:"signature,omitempty"`
}
var blk = []Blk{
{Header: Header{
Parent: "0000000000000000000000000000000000000000000000000000000000000000",
Number: 0,
Nonce: 1548399560,
Time: 1609374088,
Miner: "0x699ecb24665b9734c420db0f75ed9677a8615eb1",
aluckdog1回答
-
米琪卡哇伊
所以，我把 graphql 模式改成了：var blockType = graphql.NewObject( graphql.ObjectConfig{ Name: "block", Fields: graphql.Fields{ "header" :&graphql.Field{ Type: headerType, }, "payload": &graphql.Field{ Type: graphql.NewList(payloadType), }, }, })var payloadType = graphql.NewObject( graphql.ObjectConfig{ Name: "payload", Fields: graphql.Fields{ "from": &graphql.Field{ Type: graphql.String, }, "to": &graphql.Field{ Type: graphql.String, }, "value": &graphql.Field{ Type: graphql.Int, }, "nonce": &graphql.Field{ Type: graphql.Int, }, "data": &graphql.Field{ Type: graphql.String, }, "time": &graphql.Field{ Type: graphql.Int, }, "signature": &graphql.Field{ Type: graphql.String, }, }, })var headerType = graphql.NewObject( graphql.ObjectConfig{ Name: "header", Fields: graphql.Fields{ "parent": &graphql.Field{ Type: graphql.String, }, "number": &graphql.Field{ Type: graphql.Int, }, "nonce": &graphql.Field{ Type: graphql.Int, }, "time": &graphql.Field{ Type: graphql.Int, }, "miner": &graphql.Field{ Type: graphql.String, }, }, },)现在，一切都按预期工作。看来这句话是罪魁祸首： "payload": &graphql.Field{ Type: graphql.NewList(transactionType), },出于某种原因，如果你尝试做这种类型的嵌套go-graphql（或者graphql不知道该怎么做）。FWI：现在我的查询看起来像这样：query{ blocks{header{parent,number,nonce,time,miner},payload{from,to,value,nonce,data,time,signature}}}并且它们会产生所需的结果。
随时随地看视频慕课网APP
相关分类
Go