从事件处理程序更改 textBox.text

Question

似乎无法在这里找到我一生的答案。无论如何，事件处理程序如何更改 Form 的 textBox.text？

private static void DataReceivedHandler(object sender, SerialDataReceivedEventArgs e)

        {

            SerialPort sp = (SerialPort)sender;

            string indata = sp.ReadExisting();

            //Do what ever you want with the data

            textBox2.Text = "test"; //alas, this doesn't work

        }

按下按钮时创建事件处理程序

private void button3_Click(object sender, EventArgs e)

        {

                    serialPort1.PortName = comboBox1.Text;

                    serialPort1.BaudRate = Convert.ToInt32(comboBox2.Text);

                    serialPort1.RtsEnable = true;

                    serialPort1.DtrEnable = true;

                    serialPort1.DataReceived += new SerialDataReceivedEventHandler(DataReceivedHandler);

                    serialPort1.Open();

                }

            }

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Answer 1

该DataReceivedHandler方法被标记static，因此它不能访问实例成员textBox2。删除static能解决问题吗？

Answer 2

这DataReceived是在它自己的线程上，您需要调用 GUI 才能更新文本框。private void serialPort1_DataReceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e){    string Data = serialPort1.ReadExisting();    this.Invoke((MethodInvoker)delegate    {        textBox2.AppendText(Data);    });}