如何根据id获取国家名称？

Question

我有一张表，我在其中保存语言的记录 ID ( language_skills_selected)。现在，我需要为每个项目获取名称。我将名称保存在 table 中language_skills。

这是我的变量和每个人的dd：

$data['user_test'] = DB::table('language_skills_selected')->where('user_id', $id)->get();

Language: 22 - Level: Intermediate 

Language: 41 - Level: Beginner 

Language: 13 - Level: Expert 

Language: 35 - Level: Expert 

Language: 23 - Level: Intermediate 

在这里我有名字的变量： $data['language_skills'] = \App\LanguageSkill::lists('language_skill','id');

{"1":"Albanian","2":"Arabic","3":"Bengali","4":"Belarus","5":"Bulgarian","6":"Czech","7":"Chinese","8":"Korean","9":"Croatian","10":"Danish","11":"Hebraic","12":"English","13":"Estonian","14":"Finnish","15":"French","16":"German","17":"Greek","18":"Hindi","19":"Icelandic","20":"Italian","21":"Japanese","22":"Latvian","23":"Lithuanian","24":"Macedonian","25":"Hungarian","26":"Norwegian","27":"Dutch","28":"Persian","29":"Polish","30":"Portuguese","31":"Romanian","32":"Russian","33":"Serbian","34":"Slovak","35":"Slovene","36":"Spanish","37":"Swedish","38":"Thai","39":"Turkish","40":"Ukrainian","41":"Other"}

所以，而不是这些 id，我需要有语言名称 - 例如：Language: Bulgarian - Level : Expert

Answer 1

请试试这个$data['user_test'] = DB::table('language_skills_selected')      ->select("language_skills.language_skill")      ->join("language_skills","language_skills_selected.language_skills","=","language_skills.id")      ->where('language_skills_selected.user_id', $id)->get();

Answer 2

你可以使用这个代码1 -> query for Get All skills$data['user_test'] = DB::table('language_skills_selected')->where('user_id', $id)->get();2 -> Query For language_skills Name$data['language_skills'] = \App\LanguageSkill::where('id',$data['user_test']['language_skills])->get('language_skills');3 -> Set Name instead of ID$data['user_test']['language_skills'] = $data['language_skills'];您可以使用 foreach 循环；我建议更改变量的名称

Answer 3

命名约定首先，我会改变结构以使用传统的 Laravel 命名。它还可以帮助其他人更好地理解表中的关系。您已经将id其用作自动增量主键，这很好。如果您随后通过外键引用另一个表，请使用单数表名，后跟_id. 所以你的language_skills_selected表结构变成language_skills_selectedid int primaryuser_idint 外键（用户表）language_skill_idint 外键（language_skills 表）language_skillsid int 主要name字符串（名称，单数，因为其中只有一个名称）我会将列重命名language_skills为name，因为表名已经表明表中的每个条目都是语言技能。列名应该更能描述它实际包含的内容，在您的情况下，language_skills列包含名称。因此，您不妨以这种方式命名该列。连接表在 Laravel 中，您可以使用查询构建器 （参见此处）来构建查询，或者您可以使用Eloquent 模型（参见此处）。我强烈建议您仔细阅读文档的两个部分。它是框架的重要组成部分，选择何时使用取决于您的用例。现在终于到了你的解决方案。如果您更改了列名，则可以在两个表之间编写连接语句，如下所示：$data['user_test'] = DB::table('language_skills_selected')     ->join('language_skills', 'language_skills_selected.language_skill_id', '=', 'language_skills.id')     ->where('user_id', $id)     ->get();然后，您将获得一个连接结果，您也可以在其中访问 language_skill 的名称。我还建议您总体上阅读更多有关 MySQL 的信息，因为在深入了解该框架之前，这是一个很好的基础知识。查找 MySQL 连接，并阅读这样的材料。