从另一个按许多对象属性分组的对象返回数组
我有一个这样的对象数组：
let users = [
{
user :{
idUser: 2,
name: "Alain",
age: 23
},
role: {
codeRole: 'ADM',
label: 'Administrator'
},
group: {
idGroup: 3,
nomGroup: 'RH personnes'
}
},
{
user :{
idUser: 2,
name: "Alain",
age: 23
},
role: {
codeRole: 'ADM',
label: 'Administrator'
},
group: {
idGroup: 8,
nomGroup: 'Finance personnes'
}
},
{
user :{
idUser: 8,
name: "Jhon",
age: 33
},
role: {
codeRole: 'ADM',
label: 'Administrator'
},
group: {
idGroup: 3,
nomGroup: 'RH personnes'
}
},
{
user :{
idUser: 8,
name: "Jhon",
age: 33
},
role: {
codeRole: 'GEST',
label: 'RH Helper'
},
group: {
idGroup: 3,
nomGroup: 'RH personnes'
}
},
];
我想返回这个由用户对象中的用户 id 和角色对象中的代码角色所摸索的对象数组，新的密钥组为每个 id 用户和代码角色都有一个组数组，如下所示：
results = [
{
user :{
idUser: 2,
name: "Alain",
age: 23
},
role: {
codeRole: 'ADM',
label: 'Administrator'
},
groups: [{
idGroup: 3,
nomGroup: 'RH personnes'
},
{
idGroup: 8,
nomGroup: 'Finance personnes'
}]
},
{
user :{
idUser: 8,
name: "Jhon",
age: 33
},
role: {
codeRole: 'ADM',
label: 'Administrator'
},
groups: [{
idGroup: 3,
nomGroup: 'RH personnes'
}]
},
{
user :{
idUser: 8,
name: "Jhon",
age: 33
},
role: {
codeRole: 'GEST',
label: 'RH Helper'
},
groups: [{
idGroup: 3,
nomGroup: 'RH personnes'
}]
},
];
我试过减少，但我找不到怎么做？
感谢您的帮助
白衣染霜花2回答
-
慕斯709654
尝试如下。内部减少功能。查找您的组键是否已存在于结果对象中。如果不存在，则创建新对象并添加到返回对象。将当前对象的组添加到分组对象返回结果对象注意：reduce第二个参数是您的返回对象。let users = [{ user: { idUser: 2, name: "Alain", age: 23 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 3, nomGroup: 'RH personnes' } }, { user: { idUser: 2, name: "Alain", age: 23 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 8, nomGroup: 'Finance personnes' } }, { user: { idUser: 8, name: "Jhon", age: 33 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 3, nomGroup: 'RH personnes' } }, { user: { idUser: 8, name: "Jhon", age: 33 }, role: { codeRole: 'GEST', label: 'RH Helper' }, group: { idGroup: 3, nomGroup: 'RH personnes' } },];function groupBy(r, u) { // find if your group key already exists or not. let obj = r.find(x => x.user.idUser == u.user.idUser && x.role.codeRole == u.role.codeRole); // if not exist then create new object and add to return object. if (!obj) { obj = { user: u.user, role: u.role, groups: [] }; r.push(obj); } // add group from current object to grouped object obj.groups.push(u.group); // return result object return r;}// in reduce second parameter is your return object.let result = [];users.reduce(groupBy, result);console.log(result); -
沧海一幻觉
使用reduce& findIndex。在 reduce 回调函数中，使用和findIndex查找累加器中是否存在任何对象。如果存在，则更新数组并从组中推送值。idUsercodeRolegroup如果它不存在，则创建新对象并将 的值推送到group数组中let users = [{ user: { idUser: 2, name: "Alain", age: 23 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 3, nomGroup: 'RH personnes' } }, { user: { idUser: 2, name: "Alain", age: 23 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 8, nomGroup: 'Finance personnes' } }, { user: { idUser: 8, name: "Jhon", age: 33 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 3, nomGroup: 'RH personnes' } }, { user: { idUser: 8, name: "Jhon", age: 33 }, role: { codeRole: 'GEST', label: 'RH Helper' }, group: { idGroup: 3, nomGroup: 'RH personnes' } },];let newData = users.reduce((acc, curr) => { const isUserIncluded = acc.findIndex(item => curr.user.idUser === item.user.idUser && curr.role.codeRole === item.role.codeRole); if (isUserIncluded === -1) { const tempArray = []; tempArray.push(curr.group) acc.push({ ...curr, group: tempArray }) } else { acc[isUserIncluded].group.push(curr.group) } return acc;}, []);console.log(newData)
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相关分类
JavaScript