在多轨设置中使用waveform.js 库在音频中寻找位置的问题

Question

我正在使用 wavesurfer.js 库来创建多轨播放器。（https://wavesurfer-js.org/）

我的 HTML 非常简单：

<div id="player"></div>

<div id="player_controls">

    <button class="btn btn-sm btn-dark" disabled="disabled" id="btn_play"><i class="fas fa-play"></i></button>

    <button class="btn btn-sm btn-dark" disabled="disabled" id="btn_pause"><i class="fas fa-pause"></i></button>

    <button class="btn btn-sm btn-dark" disabled="disabled" id="btn_stop"><i class="fas fa-stop"></i></button>

</div>

<script src="https://cdnjs.cloudflare.com/ajax/libs/wavesurfer.js/1.3.7/wavesurfer.min.js"></script>

<script type="text/javascript" src="mixer.js"></script>

那么我的mixer.js文件如下：

var audiofiles = ["drums.wav","bass.wav","vocals.wav",];

var buttons = {

    play: document.getElementById("btn_play"),

    pause: document.getElementById("btn_pause"),

    stop: document.getElementById("btn_stop")

};

var spectrum = [];

var ready = [];

for(var i=0; i<audiofiles.length; i++){ready.push('false');}

for(var i=0; i<audiofiles.length; i++){

    spectrum[i] = WaveSurfer.create({

        container: '#player',

        progressColor: "#28a745"

    });

    

    spectrum[i].on('ready', function () {

        ready.pop();

        ready.push = 'true';

        checkAllReady();

    });

    

    spectrum[i].on('seek', function () {

        console.log(i);

        // var currentProgress = spectrum[i].getCurrentTime() / spectrum[i].getDuration();

        // for(var j=0; j<audiofiles.length; j++){

            // spectrum[j].seekTo(currentProgress);

        // }

    });

    spectrum[i].load('separations/'+audiofiles[i]);

}

function checkAllReady(){   if(!ready.includes('false')){buttons.play.disabled = false;}}

buttons.play.addEventListener("click", function(){

    for(var i=0; i<audiofiles.length; i++){spectrum[i].play();}

    buttons.stop.disabled = false;

    buttons.pause.disabled = false;

    buttons.play.disabled = true;

}, false);

然而，寻找一个位置只是重新调用相同的寻找函数，直到我得到一个Maximum call stack size exceeded错误。任何想法如何解决这个问题？

Answer 1

您是在询问所选光谱的位置吗？试试这个——如果这行得通？spectrum[i].on('seek', function (position) {&nbsp; &nbsp; &nbsp;console.log(position)});通常事件还带有事件参数，因此附加事件参数可以让您更深入地了解并控制您需要做什么。

Answer 2

解决者：spectrum[i].on('seek', function(position){&nbsp; &nbsp; console.log(position);&nbsp; &nbsp; for(var j=0; j<audiofiles.length; j++){&nbsp; &nbsp; &nbsp; &nbsp; var currentProgress = spectrum[j].getCurrentTime() / spectrum[j].getDuration();&nbsp; &nbsp; &nbsp; &nbsp; if(currentProgress!=position){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; spectrum[j].seekTo(position);&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }});