TkInter 错误：没有显示名称和 $DISPLAY 环境变量

Question

我正在 Repl.it 上研究TkInter并遇到了问题，这是我的代码：

from tkinter import *

import tkinter as tk

root = tk.Tk()

root.geometry('400x400')

我遇到了这个错误：

Traceback (most recent call last):

  File "main.py", line 4, in <module>

    root = tk.Tk()

  File "/usr/local/lib/python3.7/tkinter/__init__.py", line 202

3, in __init__

    self.tk = _tkinter.create(screenName, baseName, className,

interactive, wantobjects, useTk, sync, use)

_tkinter.TclError: no display name and no $DISPLAY environment

variable

我该如何解决这个问题？

Answer 1

您显然正在尝试使用 repl.it 的“Python”来执行此操作，它不支持 tkinter 需要的显示。他们确实提供了一个单独的“Tkinter”选项，尽管它在语言列表中很远。这是一个快捷方式：https ://repl.it/languages/tkinter在那里你没有得到那个错误。为了实际显示窗口，您还必须在当前代码下添加它：root.mainloop()演示

Answer 2

from tkinter import *&nbsp;&nbsp;&nbsp;&nbsp;top = Tk()&nbsp;&nbsp;&nbsp;&nbsp;top.geometry("400x250")&nbsp;&nbsp;&nbsp;&nbsp;#creating label&nbsp;&nbsp;uname = Label(top, text = "Username").place(x = 30,y = 50)&nbsp;&nbsp;&nbsp;&nbsp;#creating label&nbsp;&nbsp;password = Label(top, text = "Password").place(x = 30, y = 90)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;sbmitbtn = Button(top, text = "Submit",activebackground = "pink", activeforeground = "blue").place(x = 30, y = 120)&nbsp;&nbsp;&nbsp;&nbsp;e1 = Entry(top,width = 20).place(x = 100, y = 50)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;e2 = Entry(top, width = 20).place(x = 100, y = 90)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;top.mainloop()&nbsp;&nbsp;