在 Ursina 模块中调用()做什么

我导入了Ursina模块。它是一个游戏引擎。


我查了一个教程,并在代码invoke()中使用了。我试图找到文档,但似乎没有关于它的信息。教程中的代码如下所示:


from ursina import *


# create a window

app = Ursina()


# most things in ursina are Entities. An Entity is a thing you place in the world.

# you can think of them as GameObjects in Unity or Actors in Unreal.

# the first paramenter tells us the Entity's model will be a 3d-model called 'cube'.

# ursina includes some basic models like 'cube', 'sphere' and 'quad'.


# the next parameter tells us the model's color should be orange.


# 'scale_y=2' tells us how big the entity should be in the vertical axis, how tall it should be.

# in ursina, positive x is right, positive y is up, and positive z is forward.


player = Entity(model='cube', color=color.orange, scale_y=2)


# create a function called 'update'.

# this will automatically get called by the engine every frame.


def update():

    player.x += held_keys['d'] * time.dt

    player.x -= held_keys['a'] * time.dt


# this part will make the player move left or right based on our input.

# to check which keys are held down, we can check the held_keys dictionary.

# 0 means not pressed and 1 means pressed.

# time.dt is simply the time since the last frame. by multiplying with this, the

# player will move at the same speed regardless of how fast the game runs.



def input(key):

    if key == 'space':

        player.y += 1

        invoke(setattr, player, 'y', player.y-1, delay=.25)



# start running the game

app.run()

请帮我。


PS我正在使用Linux Mint。


慕桂英4014372
浏览 232回答 1
1回答

郎朗坤

它用于延迟调用函数,类似于 Unity 中的 Invoke()。所以在这种情况下,它会在 0.25 秒后将 player.y 减少 1。调用(函数,*args,**kwargs)编辑:文档中的示例:def test_func(item, x=None, y=None):    print(item, x, y)test_func('test')invoke(test_func, 'test', delay=.1)invoke(test_func, 'test1', 1, 2, delay=.2)invoke(test_func, 'test2', x=1, y=2, delay=.3)`
打开App,查看更多内容
随时随地看视频慕课网APP

相关分类

Python