PHP Json 文件合并
我需要将 json 文件合并到 1 个文件中。
我在 3 个文件中有这样的 json
{
"count": 2077,
"records": [
{
"comm_date": "51529",
"Certificate_Number": "31",
},
{
"comm_date": "51529",
"Certificate_Number": "31",
}
]}
但是探针是因为我有计数和记录数组在这里所以它没有成功合并
<?php
$a1 = file_get_contents ("EngroClaims.json");
$a2 = file_get_contents ("EngroClaims2.json");
$a6 = file_get_contents ("SCB1Claims.json");
$a7 = file_get_contents ("TotalParcoClaims.json");
$a8 = file_get_contents ("SAPTClaims.json");
$r = array_merge(json_decode($a1,true), json_decode($a2,true), json_decode($a6,true), json_decode($a7,true), json_decode($a8,true));
file_put_contents('conventional.json', json_encode($r));
?>
这是我的 php 代码，它工作正常。但我需要合并所有数组records
例子
第一个文件
{
"count": 2,
"records": [
{
"comm_date": "1",
},
{
"comm_date": "2",
}
]}
第二个文件
{
"count": 3,
"records": [
{
"comm_date": "1",
},
{
"comm_date": "2",
},
{
"comm_date": "3",
}
]}
预期结果
{
"count": 9, //this count value is not imprtant assume it will show 1
"records": [
{
"comm_date": "1",
},
{
"comm_date": "2",
},
{
"comm_date": "1",
},
{
"comm_date": "2",
},
{
"comm_date": "3",
}
]}
慕勒34288722回答
-
九州编程
您可以使用这种方式；<?php$a1 = file_get_contents ("EngroClaims.json");$a2 = file_get_contents ("EngroClaims2.json");$a1 = json_decode($a1, true);$a2 = json_decode($a2, true);$count = $a1["count"] + $a2["count"];$data = array();$data["count"] = $count;foreach ($a1["records"] as $row) { $data["records"][] = $row;}foreach ($a2["records"] as $row) { $data["records"][] = $row;}echo json_encode($data);我发现了你的问题。去掉 json 中的逗号（代码中有解释）。$a1 = '{ "count": 2077, "records": [{ "comm_date": "51529", "Certificate_Number": "31", <--- THIS IS A PROBLEM},{ "comm_date": "51529", "Certificate_Number": "31", <--- THIS IS A PROBLEM}]}';/* in order for this solution to work you need to delete that comma. Because there isn't a following data in the json so the comma should not be there */检查此链接； http://sandbox.onlinephpfunctions.com/code/8dfab10352cf4966c95eb599d2ed8644b24b49ab -
繁星淼淼
如果不需要计数，可以使用 array_merge_recursive$r = array_merge_recursive(json_decode($a1,true), json_decode($a2,true),json_decode($a3,true)); echo json_encode($r);会给你结果{"count":[3,3,3],"records":[{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"},{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"},{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"}]}
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