我已经使用类型(选择)、名称(文本)、单位(选择)创建了动态行,我正在为更改类型的选择编写代码。但是,当我从类型字段中更改值时,它已将值加载到当前行名称字段中,并将选项动态加载到当前单元选择字段中,将值加载到活动行中工作正常,但将选项加载到选择单元中则不行。
我的代码如下
$(document).on('change', '.raw', function () {
// var r = this.val();
if ($(this).val() != 0) {
var t = $(this).parents('tr').find(".raw :selected").text();
$(this).parents('tr').find(".name").val(t);
我需要帮助的地方如下
$(this).parents('tr').find(".amount").html(data); -> here i need help
// $(".amount").html(data); ->this working fine but change all the select value
提前致谢。这是我的表的完整编码
<table id="addingtable" class="table table-bordered">
<tr>
<th>Raw Master</th>
<th>Name</th>
<th>Display</th>
<th>Value</th>
<th>Unit</th>
<th>Delete</th>
</tr>
<tr>
<td><select name='rawmaster[]' class = 'form-control raw' required><option>Select</option><?php echo rawmaster_item($conn,$type); ?><option value="0">None</option></select></td>
<td><input type='text' name='name[]' placeholder="Name" class = 'form-control name' required /></td>
<td><select name='des[]' class = 'form-control' required><option>Select</option><option Value = 'y'>Yes</option><option Value = 'n'>No</option></select></td>
<td><input type='text' name='value[]' placeholder="Value" class = 'form-control' required /></td>
<td><select name='amount[]' class = 'form-control amount' required><option>Select</option><?php echo $output2; ?></select></td>
<td><button type='button' class='btn btn-icon btn-danger remove'><i class='feather icon-trash-2'></i></button></td>
</tr>
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