我需要使用 javascript 从结果 json 文件中删除不必要的 json 对象

3回答

吃鸡游戏

遍历数组，查看每个对象，然后通过复制所需的数据来创建一个新数组。例如，我认为如果对象的错误数组为空，则您不关心对象，并且您schema永远不关心：let newJSON = [];//Assume the json variable is the parsed JSON file you posted.for (let element of json) {    //Must have at least one error    if (element.errors.length > 0) {        //Create a new object        let newObj = {            "product_id" : element.product_id,            "errors" : []        };        //Add each errror        for (let error of element.errors) {            //Only copy across what we need            newObj.errors.push({                "property" : error.property,                "message" : error.message            });        }        //Add object to our new array of JSON        newJSON.push(newObj);    }}//newJSON is your processed JSON output

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浮云间

最简单的解决方案可以是：const records = [{  "product_id": "learningstudio",  "errors": []},{  "product_id": "pearsontestprep",  "errors": []},{  "product_id": "equella",  "errors": [{    "property": "instance.test_ids[1]",    "message": "requires property \"maintenance\"",    "schema": {      "$id": "#/properties/test_ids/items",     }  }]}];const filteredRecords = records.map((record) => {  record.errors = record.errors.map((error) => {    return {property: error. property, message: error.message};  });  return record;  });console.log(filteredRecords);

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函数式编程

您可以使用映射和解构分配来仅捕获所需的属性let json = [{"product_id": "equella", "errors": [{"property": "instance.test_ids[1]","message": "requires property \"maintenance\"",'xyz': 'not needed','useless': 'not needed',},{'xyz': 'not needed',}]},] let op = json.map(({product_id,errors}) =>{  let { property, message } = errors[0] return { product_id, errors: {property,message}}})  console.log(op)

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