Laravel 根据关系结果返回数据
PostController.php
$customers = $query->orderBy('id', 'desc')->with('agents:agents.id')->get();
foreach ($customers as $customer) {
$customer->calculator = $this->calculator($customer);
}
return response()->json($customers, 200 );
Post.php
function agents()
{
return $this->belongsToMany('App\Agent','files','post_id','agent_id');
}
这将返回正确的数据，如下所示：
[{
"id": 5,
"hash": "SqB29tkfm1dwGsXp4ZCV",
"agents": [{
"id": 1,
"pivot": {
"post_id": 5,
"agent_id": 1
}
}]
},
{
"id": 4,
"hash": "SqH29tkfm1dwGsXp4ZCV",
"agents": []
},
{
"id": 3,
"hash": "RqH29tkfm1dwGsXp4ZCV",
"agents": [{
"id": 1,
"pivot": {
"post_id": 3,
"agent_id": 1
}
}]
},
{
"id": 1,
"hash": "RqH29tkfm1dwGrXp4ZCV",
"agents": [{
"id": 1,
"pivot": {
"post_id": 1,
"agent_id": 1
}
}]
}
]
但我想要的是只返回那些有空代理的数据[]，在这种情况下，应该只返回 id4因为代理数组是空的。我怎样才能做到这一点？
狐的传说2回答
-
红糖糍粑
尝试这个 ：$customers = $query->orderBy('id', 'desc')->whereDoesntHave('agents')->get();如果你想得到没有代理的客户。在这里阅读更多 -
临摹微笑
你可以同时使用 dontHave 或 whereDoesntHave like$customers = $query->orderBy('id', 'desc')->doesntHave('agents')->get();或者$customers = $query->orderBy('id', 'desc')->whereDoesntHave('agents')->get();
随时随地看视频慕课网APP
PHP