添加数组的连续元素

Question

尝试将数组的两个元素相加，即

• [2,4,6,8,10,12] 应该返回一个新数组 [6, 14, 22] (2+4, 6+8, 10+12)

• [4,2,7,15,35,23] 应该返回一个新数组 [6,22,58] - (4+2, 7+15, 35+23)

新的、沮丧的并且无法正确地制定一个 for 循环来达到预期的结果。

到目前为止我尝试过的错误解决方案：

 var newArray = [];

  for (let i = 0; i<numbers.length - 1; i +=2) {

    newArray = numbers.push(numbers[i] + numbers[i] + 1);

    console.log(newArray);

  }

Answer 1

你很接近：let newArray = [];const numbers = [2,4,6,8,10,12];for (let i = 0; i < numbers.length - 1; i += 2) {&nbsp; newArray.push(numbers[i] + numbers[i + 1]);}console.log(newArray);

Answer 2

快速简单，假设输入总是一个偶数长度的数组const data = [4,2,7,15,35,23]const length = data.lengthconst res = []for(let i = 0; i < length; i+=2){&nbsp; var num1 = data[i]&nbsp; var num2 = data[i + 1]&nbsp; res.push(num1 + num2)}console.log(res)