如何使用 split() 命令来计算 txt 中的特定单词

Question

我有一个txt文件，我想使用 list comprehension 和 command导出所有以'F'或'f'split()开头的单词。

count = []

with open('data.txt','r') as myfile:

    count = [line for line in myfile.split() if (line[0]=='F' or line[0]=='f')]

print(count)

我采取以下错误

'_io.TextIOWrapper' 对象没有属性 'split'

因此，有没有其他方法可以使用列表理解和命令拆分以获得所需的结果？

Answer 1

您想要拆分行字符串，而不是文件对象（您从中读取字符串）：with open('data.txt','r') as myfile:    count = [word             for line in myfile             for word in line.split()             if word.lower().startswith('f')]print(count)列表理解中的连续 for 循环有效地将文件扁平化为 (f-) 个单词的列表。如果您对单词本身不感兴趣并且只想要计数，您可以这样做with open('data.txt','r') as myfile:    # This works because bool inherits int, and True acts like 1, False like 0    count = sum(word.lower().startswith('f')                for line in myfile                for word in line.split())print(count)最后，如果您想要所有计数，请使用Counter：from collections import Counterwith open('data.txt','r') as myfile:    count = Counter(word.lower()[0]                    for line in myfile                    for word in line.split())print(count['f'])

Answer 2

你可以试试这个Python 脚本count = []with open('data.txt','r') as myfile:    # remove len if you only need the words starting with `f`    count = len([word for word in myfile.read().replace("\n"," ").split(" ") if word.lower()[0] == "f"])print(count)输入文件Sample line inside a File which is a FileAnother line in the file with the word File输出4在此处查看实际操作你可以if word.lower()[0] == "f"用if word[0] == "f" or word[0] == "F"

Answer 3

使用此输入文件：friday code floor funk而这段代码：f_words = []with open('words.txt') as myfile:    f_words = [word for word in myfile.read().split(" ") if word[0].lower() == 'f']print(f_words)我得到这个输出：['friday', 'floor', 'funk']