访问函数内部定义的列表

Question

运行代码时，它会按计划要求输入，但未定义列表 alpha。

首先输入没有读取，所以我更改了缩进，但是没有解决定义问题。

def newclassification1(alpha,bravo):

        alpha = ["Jacob", "Jane", "Jim"]

        bravo = ["Male", "Female", "Unknown"]

    name = input("What is the persons name?")

    if name in alpha:

        while True:

            print(bravo[alpha.index(name)])

    else:

        print("The persons name is not in the register.")

错误信息：

Traceback（最近一次调用最后一次）：文件“”，第 7 行，在 NameError：名称 'alpha' 未定义

Answer 1

我不知道您的最终目的，但这两个代码在Python3上没有任何错误。第一个：def newclassification1(alpha,bravo):    name = input("What is the persons name?")    if name in alpha:        while True:            print(bravo[alpha.index(name)])    else:        print("The persons name is not in the register.")newclassification1(["Jacob", "Jane", "Jim"], ["Male", "Female", "Unknown"])第二个：def newclassification1(alpha,bravo):    alpha = ["Jacob", "Jane", "Jim"]    bravo = ["Male", "Female", "Unknown"]    name = input("What is the persons name?")    if name in alpha:        while True:            print(bravo[alpha.index(name)])    else:        print("The persons name is not in the register.")newclassification1([], [])

Answer 2

正如其他人所指出的，您应该修复缩进，并用您的论点找出一些东西。首先，当你在函数中定义alpha和bravo时，每次调用它们都会被重写，我想你不希望发生这种情况。其次，你应该修复缩进。我建议有以下几点：def newclassification1(alpha=["Jacob", "Jane", "Jim"],bravo=["Male", "Female", "Unknown"]):        name = input("What is the persons name?")        if name in alpha:            print(bravo[alpha.index(name)])        else:            print("The persons name is not in the register.")这样，默认情况下，您将使用您的alpha=["Jacob", "Jane", "Jim"]，bravo=["Male", "Female", "Unknown"]但稍后在调用该函数时可以轻松地将其更改为您想要的任何内容。此外，您不需要while True零件，因为它会在不停止执行的情况下运行

Answer 3

def newclassification1(name):    alpha = ["Jacob", "Jane", "Jim"]    bravo = ["Male", "Female", "Unknown"]    if name in alpha:        print(bravo[alpha.index(name)])    else:        print("The persons name is not in the register.")name = input("What is the persons name?")newclassification1(name)

Answer 4

我做了一些调整，主要是从函数中删除 alpha 和 bravo。alpha = ["Jacob", "Jane", "Jim"]bravo = ["Male", "Female", "Unknown"]def newclassification1(alpha,bravo):    name = input("What is the persons name?")    if name in alpha:        print(bravo[alpha.index(name)])    else:        print("The persons name is not in the register.")newclassification1(alpha,bravo)这是可行的，因为由于您将 alpha 和 bravo 传递给函数，因此这些变量应该在函数外部定义。我也把你while改成了一个if，否则你会得到无限的输出。我正在共享的功能的输出：What is the persons name?JimUnknownWhat is the persons name?JaneFemaleWhat is the persons name?aThe persons name is not in the register.给定 OP 注释：alpha并且bravo 必须在函数中定义。def newclassification1(alpha = [],bravo = []):    alpha = ["Jacob", "Jane", "Jim"]    bravo = ["Male", "Female", "Unknown"]    name = input("What is the persons name?")    if name in alpha:        print(bravo[alpha.index(name)])    else:        print("The persons name is not in the register.")newclassification1()输出：What is the persons name?JimUnknownWhat is the persons name?TimThe persons name is not in the register.What is the persons name?JaneFemale