javascript循环数组和对象数据在一张表中
我有数组和对象数据，我想将它们一起调用。
var data = [
{"number": "PA1234","name": "John"},
{"number": "JM344","name": "jessi"},
{"number": "ML567","name": "Monty"}
];
var costing= {
"cost": 10,
"cost": 20,
"cost": 30,
};
表格显示格式
<pre>
<table>
<tr>
<td>number</td>
<td>name</td>
<td>cost</td>
</tr>
</table>
<pre>
到目前为止我已经完成了，但不知道如何调用对象成本核算
var records=$("<table/>").attr("id","tabs");
$("#table").append(records);
for(var j=0;j<data .length;j++)
{
var tr="<tr>";
var td1="<td>"+data [j]["number"]+"</td>";
var td2="<td>"+data [j]["name"]+"</td>";
$("#tabs").append(tr+td1+td2+td3);
}
长风秋雁浏览 117回答 2
2回答
-
哆啦的时光机
<!DOCTYPE html><html> <head> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script> <title> </title> <style> #t, tr, th, td{ border: 1px solid black; } </style> </head> <body> <table id="t" cellpadding="10"> <tr> <th> Number </th> <th> Name </th> <th> Cost </th> </tr> </table> </body> <script> var number = ['PA1234', 'JM344', 'ML567'], name = ['John', 'Jessi', 'Monty'], costing = [30, 30, 30]; for(var i=0;i<3;i++) { $("#t").append('<tr><td>' + number[i] + '</td><td>' + name[i] + '</td><td>' + costing[i] + '</td></tr>'); } </script></html> -
HUWWW
不得不用你的第二个对象改变一些东西，成本。我认为您不能在不同的值上使用相同的键名，您将无法迭代它们。现在你可以做两种方法： var data = [ {"number": "PA1234","name": "John"}, {"number": "JM344","name": "jessi"}, {"number": "ML567","name": "Monty"}];var costing = {"cost0": 10,"cost1": 20,"cost2": 30,};document.addEventListener("DOMContentLoaded", () => { const place = document.getElementById("place").firstElementChild const table = document.createElement("table") for(let i = 0; i < data.length; i++){ let tr = document.createElement("tr") let tdNumber = document.createElement("td") let tdName = document.createElement("td") let tdCost = document.createElement("td") tdNumber.innerText = data[i].number tdName.innerText = data[i].name tdCost.innerText = costing["cost"+i] tr.appendChild(tdNumber) tr.appendChild(tdName) tr.appendChild(tdCost) table.appendChild(tr) } place.appendChild(table)})但是我个人会将您的成本核算对象更改为： var costing2 = [ 10,20,30]并将for循环更改为：for(let i = 0; i < data.length; i++){ let tr = document.createElement("tr") let tdNumber = document.createElement("td") let tdName = document.createElement("td") let tdCost = document.createElement("td") tdNumber.innerText = data[i].number tdName.innerText = data[i].name tdCost.innerText = costing2[i] tr.appendChild(tdNumber) tr.appendChild(tdName) tr.appendChild(tdCost) table.appendChild(tr)} where place 是 html 中 div 标签的位置。不是最好的解决方案，但它可以工作，如果你想要的话，也可以放下 html 代码：<html> <head> <script src="./file.js"></script> </head> <body> <div id="place"> <pre> </pre> </div> </body></html>
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相关分类
JavaScript