如下，请问如何编写!Y=1+3+5+7+...111？

Question

求解C语言编程用do while()语句编写!Y=1+3+5+7+...111

Answer 1

手写一下，未经调试#include<stdio.h>main(){int Y=0,i=1;do{Y+=i;i+=2;}while(Y<=111);printf("%d",Y);}

Answer 2

int n=1;int s=0;do{s+=n;n+=2;}while(n<=111)

Answer 3

main(){int i,sum=0;do{sum+=i;i+=2}while(i=1&&i<=111)printf("%d",sum);}