计算范围内的时间

Question

我正在尝试学习 Python，但我陷入了日期/时间例程中，我需要查找 05:00 到 11:30 之间发生的数据，但无论我如何处理，我都会遇到错误。我认为我需要解码时间，进行数学运算，然后对时间进行编码。我确信这是一件简单的事情，但我似乎无法完成它。

例子：

riders = [

    ["rider_2391", 37_775370, -122.417571, 37_808601, -122.409807, "17:02:35", "$17.23", "UberX"],

    ["rider_1879", 37.775222, 122.47109, 37.808080, -122.410002, "06:25:08",  "$22.25", "UberX"],

    ["rider_98233", 37.784125, -122.471891, 37.763025, 122.478749, "11:48:55", "$6.28",  "Pool"]

]

def getRiderDate(riders):

    ans = []

    for rider in riders:

        if rider[5] >= "05:00:00" and rider[5] <= "11:30:00":

            ans.insert(len(ans), rider)

    return ans

print(getRiderDate(riders)

Answer 1

您的问题是循环控制错误：&nbsp; &nbsp;for rider in riders:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; if rider[5] >= "05:00:00" and rider[5] <= "11:30:00":&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ans.insert(len(ans), rider)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; return ans;无论比赛结束，您检查一名骑手并返回。尝试这个：def getRiderDate(riders):&nbsp; &nbsp; ans = []&nbsp; &nbsp; for rider in riders:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;&nbsp; &nbsp; &nbsp; &nbsp; if rider[5] >= "05:00:00" and rider[5] <= "11:30:00":&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ans.append(rider)&nbsp; &nbsp; return ans;return在循环之后，而不是在里面。输出：[['rider_1879', 37.775222, 122.47109, 37.80808, -122.410002, '06:25:08', '$22.25', 'UberX']]

Answer 2

我会使用 datetime 模块，主要是时间。还有以前的答案指出了什么（在循环内返回 ans 等）import datetimeriders = [["rider_2391", 37_775370, -122.417571, 37_808601, -122_409807, "17:02:35", "$17.23", "UberX"],&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ["rider_1879", 37.775222, 122.47109, 37.808080, -122.410002, "06:25:08", "$22.25", "UberX"],&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ["rider_98233", 37.784125, -122.471891, 37.763025, 122.478749, "11:48:55", "$6.28", "Pool"]]def getRiderDate(riders):&nbsp; &nbsp; ans = []&nbsp; &nbsp; t1 = datetime.time(hour=5)&nbsp; &nbsp; t2 = datetime.time(hour=11, minute=30)&nbsp; &nbsp; for rider in riders:&nbsp; &nbsp; &nbsp; &nbsp; t = datetime.datetime.strptime(rider[5], '%H:%M:%S').time()&nbsp; &nbsp; &nbsp; &nbsp; if t1 <= t <= t2:&nbsp; # using chained comparison&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; ans.insert(len(ans), rider)&nbsp; &nbsp; return ansprint(getRiderDate(riders))