我用谷歌搜索了这个,但他们都在谈论“交换节点而不交换数据”。
我尝试自己编写一个交换节点方法:
public void swapNodes(int num1, int num2) {
if(num1 == num2) {
return;
}
Node currentNum1 = head;
Node currentNum2 = head;
Node waitForSwap1 = null;
Node waitForSwap2 = null;
while (currentNum1 != null) {
if (currentNum1.data == num1) {
waitForSwap1 = currentNum1;
System.out.println();
System.out.println("waitForSwap 1");
System.out.println(waitForSwap1.data);
}
currentNum1 = currentNum1.next;
}
while (currentNum2 != null) {
if (currentNum2.data == num2) {
waitForSwap2 = currentNum2;
System.out.println("waitForSwap 2");
System.out.println(waitForSwap2.data);
}
currentNum2 = currentNum2.next;
}
currentNum1 = waitForSwap2;
currentNum2 = waitForSwap1;
System.out.println("currentNum1");
System.out.println(currentNum1.data);
System.out.println("currentNum2");
System.out.println(currentNum2.data);
}
这是结果
如您所见,currentNum1
并currentNum2
相互更改,但打印结果没有交换。如何交换两个节点及其数据?
侃侃尔雅
相关分类