我正在尝试将命令行参数传递给在Docker 容器中运行的Spring Boot应用程序的主要方法。从命令行运行,我会做这样的事情:
$ mvn spring-boot:run -Dspring-boot.run.arguments=--greeting=Hello,--recipient=World
应用程序需要提取这些 args 并对它们进行一些处理:
public static void main(String[] args) {
Options options = new Options();
Option greeting = new Option("-g", "greeting", true, "Greeting");
greeting.setRequired(true);
greeting.addOption(greeting);
Option recipient = new Option("-r", "recipient", true, "Recipient");
recipient.setRequired(true);
recipient.addOption(recipient);
try {
cmd = parser.parse(options, args);
} catch (ParseException e) {
System.out.println(e.getMessage());
formatter.printHelp("utility-name", options);
System.exit(1);
}
// Do some processing using these args ...
// Run the Spring Boot app
SpringApplication.run(SpringBootApp.class, args);
}
我试过简单地使用-e标志传递它们:
docker run -p 8080:8080 -d -e "greeting=Hello" -e "recipient=World" test-image
我的Dockerfile样子是这样的:
FROM openjdk:8-jdk-alpine
VOLUME /tmp
COPY ./target/spring-boot-app-0.0.1-SNAPSHOT.jar app.jar
ENTRYPOINT ["java","-Djava.security.egd=file:/dev/./urandom","-jar","/app.jar"]
由于需要选项(args),我不断收到错误消息并且应用程序退出。
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