叮当猫咪
不完全确定我明白你的意思,但如果你只是想保持频率的连续计数,字典是一个很好的方法。例如,如果我们使用虚拟数据 ['A', 'A', 'B', 'A', 'C', 'C']category_counts = {}for category in categories: try: category_counts[category] += 1 except: category_counts[category] = 1打印(类别计数)返回:{'A':3,'B':1,'C':2}编辑:因此,如果您想要计算每列的类别,则代码仅会稍微更改为:table = [['Male/Female','M','M','F','M',"F"],['Age','10-20','30-40','10-20','20-30','10-20']]category_counts = {}for column in table: category_counts[column[0]] = {} for data in column[1:]: try: category_counts[column[0]][data] += 1 except: category_counts[column[0]][data] = 1print(category_counts)哪个打印:{'男/女':{'M':3,'F':2},'年龄':{'10-20':3,'30-40':1,'20-30':1} }但我不确定您当前如何存储数据