我连接到 Kubernetes 集群中的服务器,使用 POST 请求和标头来升级请求。我正在使用以下功能:
func PostRequest(client *http.Client, url string, bodyData []byte) (*http.Response, error){
req, _ := http.NewRequest("POST", url, bytes.NewBuffer(bodyData))
//req.Header.Set("Authorization", "Bearer " + BEARER_TOKEN)
req.Header.Set("X-Stream-Protocol-Version", "v2.channel.k8s.io")
req.Header.Set("X-Stream-Protocol-Version", "channel.k8s.io")
req.Header.Set("Upgrade", "SPDY/3.1")
req.Header.Set("Connection","upgrade")
req.Header.Set("Content-Type", "application/x-www-form-urlencoded")
resp, err := (*client).Do(req)
return resp, err
}
收到回复后,我试图阅读它,但当我阅读正文时它卡住了:
url2 := "https://<serveri_ip>:10250/exec/default/mypod/mycontainer?command=ls&command=/&input=1&output=1&tty=1"
resp, err := PostRequest(api.GlobalClient, url2, []byte(""))
fmt.Println(r.Status)
fmt.Println(r.Header)
bodyBytes, err := ioutil.ReadAll(r.Body) // -> it stuck here
fmt.Println(string(bodyBytes))
我想它试图打开 websocket,所以我尝试像这样使用gorilla websocket 库:
u := url.URL{Scheme: "ws", Host: "<node_ip>:10250", Path: "/exec/default/mypod/mycontainer?command=ls&command=/&input=1&output=1&tty=1"}
interrupt := make(chan os.Signal, 1)
signal.Notify(interrupt, os.Interrupt)
c, _, err := websocket.DefaultDialer.Dial(u.String(), nil)
if err != nil {
log.Fatal("dial:", err)
}
defer c.Close()
但是它打印了一个错误:
2020/04/04 20:51:25 拨号:websocket:握手错误
我做错了什么?
如何从状态“切换协议”中读取响应正文
慕虎7371278
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