如题描述，PHP json格式如何处理替换问题？

Question

原始： {"db":"[{"0":"9","id":"9"},{"0":"9","id":"9"},]"}
我想要： {"db":[{"0":"9","id":"9"},{"0":"9","id":"9"}]}
怎么替换字符？？？

Answer 1

可以用正则$jsonStr = '{"db":"[{"0":"9","id":"9"},{"0":"9","id":"9"},]"}'; $jsonStr = preg_replace('/[\'"](\[.*?\])[\'"]/iU', '$1', $jsonStr);// 去除json串中，数组外的引号，将形如"[{...}]"替换成[{...}]$jsonStr = preg_replace('/,\s*\]/', ']', $jsonStr);// 去除json串中多余的逗号 字符串替换：$jsonStr = str_replace('"[', '[', $jsonStr);$jsonStr = str_replace(',]"', ']', $jsonStr);

Answer 2

$raw = '{"db":"[{"0":"9","id":"9"},{"0":"9","id":"9"},]"}';$obj = @json_decode($raw, TRUE);$obj['db'] = @json_decode($obj['db'], TRUE);$i_want = @json_encode($obj);