慕桂英546537
既然你标记了你的问题momentjs,这里有一个使用 moment JS 库的解决方案。首先你拆分你的字符串,然后你格式化每个日期,最后你加入字符串。注意:这会给你一个警告,因为初始日期格式不是标准化的。const dates = 'Wed Nov 13 2019 00:00:00 GMT+0000 (UTC),Tue Nov 19 2019 00:00:00 GMT+0000 (UTC),Tue Nov 19 2019 00:00:00 GMT+0000 (UTC)'const parseDates = dates => ( dates .split(',') .filter(date => moment(date).isValid()) .map(date => moment(date).format('MM/DD/YYYY')) .join(','))console.log(parseDates(dates));<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.24.0/moment.min.js"></script>否则,如果您确定您的日期将始终具有相同的格式,您可以使用正则表达式手动解析它们:const months = [ '', 'Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']const dateRegex = /[\w]{3}\s{1}([\w]{3})\s{1}(\d{2})\s{1}(\d{0,4})\s/iconst dates = 'Wed Nov 13 2019 00:00:00 GMT+0000 (UTC),Tue Nov 19 2019 00:00:00 GMT+0000 (UTC),Tue Nov 19 2019 00:00:00 GMT+0000 (UTC)'const parseDatesFallback = dates => ( dates .split(',') .map(date => { date = date.match(dateRegex) return String(months.indexOf(date[1])).padStart(2, '0') + '/' + date[2] + '/' + date[3] }) .join(','))console.log(parseDatesFallback(dates));