基于 .(dot) 的嵌套对象
我有这样的对象
var RecuiterInfo = {}
RecruiterInfo.Quote: "1"
RecruiterInfo.CompanyName: "Imperial Innovations",
RecruiterInfo.OrganizationSize: "2",
RecruiterInfo.Person.CitizanZenship: null,
RecruiterInfo.Person.DOB: "Farkhonda@hotmail.com",
RecruiterInfo.Person.Email: "Farkhonda",
RecruiterInfo.Person.FirstName: "FaiZi",
RecruiterInfo.Person.Gender: "4456565656"
RecruiterInfo.Person.LastName: "4456565656",
RecruiterInfo.Person.PhoneNo: "4456565656",
RecruiterInfo.Person.UserId.UserName: "MTIzNDU2",
RecruiterInfo.Person.UserId.Password: null
我想将此对象转换为这种特定格式
{
"QueryObjectID":"RecruiterInfo",
"Values": [
{
"AppFieldID": "Person",
"Value": [
{
"AppFieldID": "CitizanZenship",
"Value": "1"
},
{
"AppFieldID": "DOB",
"Value": "01/01/2019"
},
{
"AppFieldID": "Email",
"Value": "test1@test.com"
},
{
"AppFieldID": "FirstName",
"Value": "test"
},
{
"AppFieldID": "Gender",
"Value": "1"
},
{
"AppFieldID": "LastName",
"Value": "test last"
},
{
"AppFieldID": "PhoneNo",
"Value": "7897897895"
},
{
"AppFieldID": "UserId",
"Value": [
{
"AppFieldID": "UserName",
"Value": "test1@test.com"
},
{
"AppFieldID": "Password",
"Value": "123456"
}
]
}
]
},
但它应该是通用/动态的（我不想要任何静态的东西，因为在功能中会有多个点/或嵌套对象）我认为循环将基于.（点），它会嵌套不确定
谁能帮我这个json转换
三国纷争2回答
-
Qyouu
您可以递归地执行此操作。const convert = (obj) => { if (obj === null) return null if (typeof obj !== 'object') return obj return Object.entries(obj) .reduce((acc, [key, value]) => acc.concat({ AppFieldId: key, Value: convert(value), // Recursive call }), [])}console.log(JSON.stringify(convert(RecruiterInfo), null, 2))这并不完全像你想要的那样，但你首先需要静态的东西。[ { "AppFieldId": "Quote", "Value": "1" }, { "AppFieldId": "CompanyName", "Value": "Imperial Innovations" }, { "AppFieldId": "OrganizationSize", "Value": "2" }, { "AppFieldId": "Person", "Value": [ { "AppFieldId": "CitizanZenship", "Value": null }, { "AppFieldId": "DOB", "Value": "Farkhonda@hotmail.com" }, { "AppFieldId": "Email", "Value": "Farkhonda" }, { "AppFieldId": "FirstName", "Value": "FaiZi" }, { "AppFieldId": "Gender", "Value": "4456565656" }, { "AppFieldId": "LastName", "Value": "4456565656" }, { "AppFieldId": "PhoneNo", "Value": "4456565656" }, { "AppFieldId": "UserId", "Value": [ { "AppFieldId": "UserName", "Value": "MTIzNDU2" }, { "AppFieldId": "Password", "Value": null } ] } ] }] -
幕布斯7119047
您可以采用迭代方法。var data = { 'RecruiterInfo.Quote': "1", 'RecruiterInfo.CompanyName': "Imperial Innovations", 'RecruiterInfo.OrganizationSize': "2", 'RecruiterInfo.Person.CitizanZenship': null, 'RecruiterInfo.Person.DOB': "Farkhonda@hotmail.com", 'RecruiterInfo.Person.Email': "Farkhonda", 'RecruiterInfo.Person.FirstName': "FaiZi", 'RecruiterInfo.Person.Gender': "4456565656", 'RecruiterInfo.Person.LastName': "4456565656", 'RecruiterInfo.Person.PhoneNo': "4456565656", 'RecruiterInfo.Person.UserId.UserName': "MTIzNDU2", 'RecruiterInfo.Person.UserId.Password': null }, result = Object.entries(data).reduce((r, [s, v]) => { var path = s.split('.'), last = path.pop(); path .reduce((o, k, i) => { var temp = o.find(q => q[i ? 'AppFieldID' : 'QueryObjectID'] === k); if (!temp) o.push(temp = i ? { AppFieldID: k, Value: [] } : { QueryObjectID: k, Values: [] }); return temp[i ? 'Value' : 'Values']; }, r) .push({ AppFieldID: last, Value: v }); return r; }, []);console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }
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JavaScript