我不能在 golang 中使用变量进行时间计算吗?

我正在尝试计算 10 分钟前的时间。为什么我不能用变量进行这个计算(可用于 for 循环)。看 -


package main


import (

    "fmt"

    "time"

)


func main() {


    // the time now

    fmt.Println(time.Now())


    // the time 50 minutes ago - WORKS

    diff := (60 - 10) * time.Minute

    newTime := time.Now().Add(-diff)

    fmt.Println(newTime)


    // the time 50 minutes ago - DOESN'T WORKS!

    i := 10

    diff = (60 - i) * time.Minute

    newTime = time.Now().Add(-diff)

    fmt.Println(newTime)

}

为什么diff = (60 - i) * time.Minute不起作用?这是我得到的错误 -


prog.go:20: invalid operation: (60 - i) * time.Minute (mismatched types int and time.Duration)

去游乐场:https : //play.golang.org/p/TJ03K0ULg2


慕丝7291255
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2回答

慕勒3428872

就像错误所说的那样,您的类型不匹配。将整数结果转换为 a time.Duration:diff = time.Duration(60-i) * time.Minute

狐的传说

time.Duration实际上是类型int64,所以如果你想使用变量来制作你想要的东西,只需将变量声明为time.Duration,就像这样:package mainimport (    "fmt"    "time")func main() {    // the time now    fmt.Println(time.Now())    // the time 50 minutes ago - WORKS    diff := (60 - 10) * time.Minute    newTime := time.Now().Add(-diff)    fmt.Println(newTime)    // the time 50 minutes ago - DOESN'T WORKS!    var i time.Duration    diff = (60 - i) * time.Minute    newTime = time.Now().Add(-diff)    fmt.Println(newTime)}
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